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Python program to extract the Unique Dictionary Value List elements
  • Last Updated : 11 Oct, 2020

Given Dictionary with value lists, extract all unique values. 

Input : test_dict = {“Gfg” : [6, 7, 4, 6], “Geeks” : [6, 8, 5, 2]} 
Output : [6, 7, 4, 8, 5, 2] 
Explanation : All distincts elements extracted.

Input : test_dict = {“Gfg” : [6, 7, 6], “Geeks” : [6, 8, 5, 2]} 
Output : [6, 7, 8, 5, 2] 
Explanation : All distincts elements extracted. 

Method #1 : Using loop 

This is brute way in which this task can be performed. In this, we memoize elements when they occur and prevent them from re enter to result list.



Python3




# Python3 code to demonstrate working of 
# Unique Dictionary Value List elements
# Using loop
  
# initializing dictionary
test_dict = {"Gfg" : [6, 7, 4, 6], 
             "is" : [8, 9, 5], 
             "for" : [2, 5, 3, 7], 
             "Geeks" : [6, 8, 5, 2]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# list to memorize elements and insert result
res = []
for sub in test_dict:
    for ele in test_dict[sub]:
          
        # testing for existence
        if ele not in res:
            res.append(ele)
  
# printing result 
print("Extracted items : " + str(res)) 

Output:

The original dictionary is : {‘Gfg’: [6, 7, 4, 6], ‘is’: [8, 9, 5], ‘for’: [2, 5, 3, 7], ‘Geeks’: [6, 8, 5, 2]}

Extracted items : [6, 7, 4, 8, 9, 5, 2, 3]

Method #2 : Using set() + union()

The combination of the above functions can be used to solve this problem. In this, we convert all lists using set() and then perform a union of all elements across all keys to get the desired result.

Python3




# Python3 code to demonstrate working of 
# Unique Dictionary Value List elements
# Using set() + union()
  
# initializing dictionary
test_dict = {"Gfg" : [6, 7, 4, 6], 
             "is" : [8, 9, 5], 
             "for" : [2, 5, 3, 7], 
             "Geeks" : [6, 8, 5, 2]}
  
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
  
# using * operator to get union 
res = list(set().union(*test_dict.values()))
  
# printing result 
print("Extracted items : " + str(res)) 

Output:

The original dictionary is : {‘Gfg’: [6, 7, 4, 6], ‘is’: [8, 9, 5], ‘for’: [2, 5, 3, 7], ‘Geeks’: [6, 8, 5, 2]}

Extracted items : [6, 7, 4, 8, 9, 5, 2, 3

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