Python PRAW – Check whether a redditor has Reddit premium or not

In Reddit, a redditor is the term given to a user. Reddit allows redditors to avail premium access by paying a fee. Here we will see how to check whether a redditor has the premium access or not. We will be using the is_gold attribute of the Redditor class to check whether a redditor has the premium access or not.

Example 1 : Consider the following redditor :

The user name of the redditor is : spez.

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# importing the module
import praw
  
# initialize with appropriate values
client_id = ""
client_secret = ""
username = ""
password = ""
user_agent = ""
  
# creating an authorized reddit instance
reddit = praw.Reddit(client_id = client_id, 
                     client_secret = client_secret, 
                     username = username, 
                     password = password,
                     user_agent = user_agent) 
  
# the name of the redditor
redditor_name = "spez"
  
# instantiating the Redditor class
redditor = reddit.redditor(redditor_name)
  
print("Does " + redditor_name + " has an active Reddit Premium status? : " +
      str(redditor.is_gold))

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Output :

Does spez has an active Reddit Premium status? : True

Example 2 : Consider the following redditor :



The user name of the redditor is : AutoModerator

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# importing the module
import praw
  
# initialize with appropriate values
client_id = ""
client_secret = ""
username = ""
password = ""
user_agent = ""
  
# creating an authorized reddit instance
reddit = praw.Reddit(client_id = client_id, 
                     client_secret = client_secret, 
                     username = username, 
                     password = password,
                     user_agent = user_agent) 
  
# the name of the redditor
redditor_name = "AutoModerator"
  
# instantiating the Redditor class
redditor = reddit.redditor(redditor_name)
  
print("Does " + redditor_name + " has an active Reddit Premium status? : " +
      str(redditor.is_gold))

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Output :

Does AutoModerator has an active Reddit Premium status? : True

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