# Python – Match Kth number digit in list elements

• Last Updated : 29 Dec, 2019

Sometimes we may face a problem in which we need to find for a list if it contains numbers at Kth index with the same digits. This particular utility has an application in day-day programming. Let’s discuss certain ways in which this task can be achieved.

Method #1 : Using list comprehension + `map()`
We can approach this problem by converting the elements to the strings and then testing the Kth element of string and if they are equal we can return true and then convert to set and test for size of result to be one. The conversion is done by map, set function converts to set and list comprehension checks for Kth element of string.

 `# Python3 code to demonstrate``# Kth Number digit match``# using list comprehension + map()`` ` `# initializing list ``test_list ``=` `[``467``, ``565``, ``2645``, ``8668``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1`` ` `# using list comprehension + map()``# Kth Number digit match``res ``=` `len``(``set``(sub[K] ``for` `sub ``in` `map``(``str``, test_list))) ``=``=` `1`` ` `# print result``print``(``"Does each element of index K have same digit ? "` `+` `str``(res))`

Output :

```The original list : [467, 565, 2645, 8668]
Does each element of index K have same digit ? True
```

Method #2 : Using `all()` + list comprehension
This is yet another approach in which this problem can be solved. In this we use all function to check for all elements and return a Boolean result and list comprehension does the part of conversion of string by str function and checking for all elements with the Kth digit of Kth element.

 `# Python3 code to demonstrate``# Kth Number digit match``# using list comprehension + all()`` ` `# initializing list ``test_list ``=` `[``467``, ``565``, ``2645``, ``8668``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# initializing K ``K ``=` `1`` ` `# using list comprehension + all()``# Kth Number digit match``res ``=` `all``(``str``(i)[K] ``=``=` `str``(test_list[K])[K] ``for` `i ``in` `test_list)`` ` `# print result``print``(``"Does each element of index K have same digit ? "` `+` `str``(res))`

Output :

```The original list : [467, 565, 2645, 8668]
Does each element of index K have same digit ? True
```

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