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Python list | pop()

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  • Difficulty Level : Basic
  • Last Updated : 22 Jun, 2022

Python list pop() is an inbuilt function in Python that removes and returns the last value from the List or the given index value.

Syntax:

list_name.pop(index)

Parameter: 

  • index (optional) – The value at index is popped out and removed. If the index is not given, then the last element is popped out and removed.

Returns: The last value or the given index value from the list.

Exception: When the index is out of range, it returns IndexError.

Example 1: Using pop() Method

Python3




# Python3 program for pop() method
 
list1 = [ 1, 2, 3, 4, 5, 6 ]
 
# Pops and removes the last element from the list
print(list1.pop())
 
# Print list after removing last element
print("New List after pop : ", list1, "\n")
 
list2 = [1, 2, 3, ('cat', 'bat'), 4]
 
# Pop last three element
print(list2.pop())
print(list2.pop())
print(list2.pop())
 
# Print list
print("New List after pop : ", list2, "\n")

Output: 

6
New List after pop :  [1, 2, 3, 4, 5] 

4
('cat', 'bat')
3
New List after pop :  [1, 2] 

Example 2

Python3




# Python3 program showing pop() method
# and remaining list after each pop
 
list1 = [ 1, 2, 3, 4, 5, 6 ]
 
# Pops and removes the last
# element from the list
print(list1.pop(), list1)
 
# Pops and removes the 0th index
# element from the list
print(list1.pop(0), list1)

Output:

6 [1, 2, 3, 4, 5]
1 [2, 3, 4, 5]

Example 3: Demonstrating IndexError 

Python3




# Python3 program for error in pop() method
 
list1 = [ 1, 2, 3, 4, 5, 6 ]
print(list1.pop(8))

Output: 

Traceback (most recent call last):
  File "/home/1875538d94d5aecde6edea47b57a2212.py", line 5, in 
    print(list1.pop(8))
IndexError: pop index out of range

Example 4: Practical Example

A list of the fruit contains fruit_name and property saying its fruit. Another list consume has two items juice and eat. With the help of pop() and append() we can do something interesting. 

Python3




# Python3 program demonstrating
# practical use of list pop()
 
fruit = [['Orange','Fruit'],['Banana','Fruit'], ['Mango', 'Fruit']]
consume = ['Juice', 'Eat']
possible = []
 
# Iterating item in list fruit
for item in fruit :
     
    # Iterating use in list consume
    for use in consume :
         
        item.append(use)
        possible.append(item[:])
        item.pop(-1)
print(possible)

Output: 

[['Orange', 'Fruit', 'Juice'], ['Orange', 'Fruit', 'Eat'],
 ['Banana', 'Fruit', 'Juice'], ['Banana', 'Fruit', 'Eat'],
 ['Mango', 'Fruit', 'Juice'], ['Mango', 'Fruit', 'Eat']]

Time Complexity : 

Complexity of all above examples is constant O(1) in both average and amortized case 


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