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Python – List Elements Grouping in Matrix
• Last Updated : 02 Sep, 2020

Given a Matrix, for groups according to list elements, i.e each group should contain all elements from List.

Input : test_list = [[2, 6], [7, 8], [1, 4]], check_list = [1, 2, 4, 6]
Output : [[7, 8], [[1, 2], [4, 6]]]
Explanation : 1, 2, 4, 6 elements rows are grouped.

Input : test_list = [[2, 7], [7, 8], [1, 4]], check_list = [1, 2, 4, 6]
Output : [[2, 7], [7, 8], [1, 4]]
Explanation : No grouping possible.

Method : Using loop + list comprehension + Try-Except

In this, for each row in matrix, get elements missing from list, after getting elements, match with each row if we can find missing elements, if found, the new group is made.

Python3

 `# Python3 code to demonstrate working of ``# List Elements Grouping in Matrix``# Using loop `` ` `# initializing list``test_list ``=` `[[``4``, ``6``], [``1``, ``2``], [``2``, ``6``], [``7``, ``8``], [``1``, ``4``]]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initializing check_list``check_list ``=` `[``1``, ``2``, ``4``, ``6``]`` ` ` ` `res ``=` `[]``while` `test_list:``     ` `    ``# getting row``    ``sub1 ``=` `test_list.pop()``     ` `    ``# getting elements not in row``    ``sub2 ``=` `[ele ``for` `ele ``in` `check_list ``if` `ele ``not` `in` `sub1]``    ``try``:``         ` `        ``# testing if we have list of removed elements``        ``test_list.remove(sub2)``         ` `        ``# grouping if present``        ``res.append([sub1, sub2])``    ``except` `ValueError:``         ` `        ``# ungrouped. ``        ``res.append(sub1)`` ` `# printing result ``print``(``"The Grouped rows : "` `+` `str``(res))`
Output
```The original list is : [[4, 6], [1, 2], [2, 6], [7, 8], [1, 4]]
The Grouped rows : [[[1, 4], [2, 6]], [7, 8], [[1, 2], [4, 6]]]
```

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