Sometimes, while working with Python lists, we can have a problem in which we might need to group the list elements on basis of their respective consecutiveness. This kind of problem can occur while data handling. Let’s discuss certain way in which this task can be performed.
Method : Using
enumerate() + groupby() + generator function + lambda
This task can be performed using the combination of above functions. In this, we create a generator function, in which we pass the list whose index-element are accessed using
enumerate() and grouped by consecutive elements using
groupby() and lambda. Works with Python2 only
The original list is : [1, 2, 3, 6, 7, 8, 11, 12, 13] Grouped list is : [(1, 3), (6, 8), (11, 13)]
- Python | Identical Consecutive Grouping in list
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- Python | Group consecutive list elements with tolerance
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- Python | Binary element list grouping
- Python | Remove consecutive duplicates from list
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- Python | Check if list contains consecutive numbers
- Python | Average of each n-length consecutive segment in a list
- Python | Grouping dictionary keys by value
- Python | Replace elements in second list with index of same element in first list
- Python | Sorting list of lists with similar list elements
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