Python | Grouping list values into dictionary

Sometimes, while working with data, we can be encountered with a situation in which we have list of list and we need to group it’s 2nd index with the common initial element in lists. Let’s discuss way in which this problem can be solved.

Method : Using `defaultdict()` + loop + `dict()`

The defaultdict can be used to initialize the group elements and loop can be used to group the values together and conversion to dictionary can be done using `dict()`.

 `# Python3 code to demonstrate working of ` `# Grouping list values into dictionary ` `# Using defaultdict() + loop + dict() ` `from` `collections ``import` `defaultdict ` ` `  `# initializing list ` `test_list ``=` `[[``'Gfg'``, ``1``], [``'Gfg'``, ``2``], [``'is'``, ``3``], [``'best'``, ``4``], [``'is'``, ``5``]] ` ` `  `# printing original list ` `print``(``"The original list is : "` `+` `str``(test_list)) ` ` `  `# Grouping list values into dictionary ` `# Using defaultdict() + loop + dict() ` `temp ``=` `defaultdict(``list``) ` `for` `key, val ``in` `test_list: ` `    ``temp[key].append(val) ` `res ``=` `dict``((key, ``tuple``(val)) ``for` `key, val ``in` `temp.items()) ` ` `  `# printing result ` `print``(``"The grouped dictionary is :  "` `+` `str``(res)) `

Output :

```The original list is : [['Gfg', 1], ['Gfg', 2], ['is', 3], ['best', 4], ['is', 5]]
The grouped dictionary is :  {'Gfg': (1, 2), 'best': (4, ), 'is': (3, 5)}
```

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