Python – Find all the strings that are substrings to the given list of strings
Given two lists, the task is to write a Python program to extract all the strings which are possible substring to any of strings in another list.
Example:
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Input : test_list1 = [“Geeksforgeeks”, “best”, “for”, “geeks”], test_list2 = [“Geeks”, “win”, “or”, “learn”]
Output : [‘Geeks’, ‘or’]
Explanation : “Geeks” occurs in “Geeksforgeeks string as substring.
Input : test_list1 = [“geeksforgeeks”, “best”, “4”, “geeks”], test_list2 = [“Geeks”, “win”, “or”, “learn”]
Output : []
Explanation : No substrings found.
Method #1 : Using list comprehension
In this, we perform task of using nested loop and testing using list comprehension, extracting the string if its part of any substring of other list.
Python3
# Python3 code to demonstrate working of# Substring Intersections# Using list comprehension # initializing liststest_list1 = ["Geeksforgeeks", "best", "for", "geeks"]test_list2 = ["Geeks", "win", "or", "learn"] # printing original listsprint("The original list 1 is : " + str(test_list1))print("The original list 2 is : " + str(test_list2)) # using list comprehension for nested loopsres = list( set([ele1 for sub1 in test_list1 for ele1 in test_list2 if ele1 in sub1])) # printing resultprint("Substrings Intersections : " + str(res)) |
Output:
The original list 1 is : [‘Geeksforgeeks’, ‘best’, ‘for’, ‘geeks’]
The original list 2 is : [‘Geeks’, ‘win’, ‘or’, ‘learn’]
Substrings Intersections : [‘or’, ‘Geeks’]
Method #2 : Using any() + generator expression
In this, any() is used to check for substring matching in any of the strings from the string list to be matched in.
Python3
# Python3 code to demonstrate working of# Substring Intersections# Using any() + generator expression # initializing liststest_list1 = ["Geeksforgeeks", "best", "for", "geeks"]test_list2 = ["Geeks", "win", "or", "learn"] # printing original listsprint("The original list 1 is : " + str(test_list1))print("The original list 2 is : " + str(test_list2)) # any() returns the string after match in any string# as Substringres = [ele2 for ele2 in test_list2 if any(ele2 in ele1 for ele1 in test_list1)] # printing resultprint("Substrings Intersections : " + str(res)) |
Output:
The original list 1 is : [‘Geeksforgeeks’, ‘best’, ‘for’, ‘geeks’]
The original list 2 is : [‘Geeks’, ‘win’, ‘or’, ‘learn’]
Substrings Intersections : [‘Geeks’, ‘or’]
