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Python | Custom slicing in List
• Last Updated : 05 Sep, 2019

Sometimes, while working with Python, we can come to a problem in which we need to perform the list slicing. There can be many variants of list slicing. One can have custom slice interval and slicing elements. Let’s discuss problem to such problem.

Method : Using `compress() + cycle()`
The combination of above functions can be used to perform this particular task. In this, we filter the list for Truth value of required elements and eliminate those which should be skipped by providing then a boolean false. Then the result is accumulated using inbuilt `compress()`

 `# Python3 code to demonstrate working of``# Custom slicing in List``# using compress() + cycle()``from` `itertools ``import` `cycle, compress`` ` `# initialize lists``test_list ``=` `[``1``, ``2``, ``4``, ``7``, ``3``, ``8``, ``6``, ``2``, ``10``, ``11``, ``17``, ``34``, ``23``, ``21``]`` ` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))`` ` `# initialize interval``interval ``=` `5`` ` `# initialize element number ``ele_num ``=` `4`` ` `# Custom slicing in List``# using compress() + cycle()``temp ``=` `cycle([``True``] ``*` `ele_num ``+` `[``False``] ``*` `interval)``res ``=` `list``(compress(test_list, temp))`` ` `# printing result``print``(``"Custom sliced list is : "` `+` `str``(res))`
Output :
```The original list is : [1, 2, 4, 7, 3, 8, 6, 2, 10, 11, 17, 34, 23, 21]
Custom sliced list is : [1, 2, 4, 7, 11, 17, 34, 23]
```

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