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Python | Count occurrences of an element in a Tuple

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In this program, we need to accept a tuple and then find the number of times an item is present in the tuple. This can be done in various ways, but in this article, we will see how this can be done using a simple approach and how inbuilt functions can be used to solve this problem. 

Examples:

Tuple: (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
Input : 4
Output : 0 times

Input : 10
Output : 3 times

Input : 8
Output : 4 times

Method 1(Simple Approach): 

We keep a counter that keeps on increasing if the required element is found in the tuple. 

Python3

# Program to count the number of times an element
# Present in the list
 
 
def countX(tup, x):
    count = 0
    for ele in tup:
        if (ele == x):
            count = count + 1
    return count
 
 
# Driver Code
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8
 
print(countX(tup, enq))
print(countX(tup, enq1))
print(countX(tup, enq2))

                    

Output
0
3
4

Method 2(Using count()): 

The idea is to use method count() to count number of occurrences. 

Python3

# Program to count the number of times an element
# Present in the list
# Count function is used
 
 
def Count(tup, en):
    return tup.count(en)
 
 
# Driver Code
tup = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
enq = 4
enq1 = 10
enq2 = 8
print(Count(tup, enq), "times")
print(Count(tup, enq1), "times")
print(Count(tup, enq2), "times")

                    

Output
0 times
3 times
4 times

Method 3: Using list comprehension

Python3

tuple1 = (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x = [i for i in tuple1 if i == 10]
print("the element 10 occurs", len(x), "times")

                    

Output
the element 10 occurs 3 times

Method #4: Using enumerate function

Python3

tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=[i for a,i in enumerate(tuple1) if i==10]
print("the element 10 occurs",len(x),"times")

                    

Output
the element 10 occurs 3 times

Method #5: Using lambda function

Python3

tuple1=(10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)
x=list(filter(lambda i: (i==10),tuple1))
print("the element 10 occurs",len(x),"times")

                    

Output
the element 10 occurs 3 times

Method #6: Using counter function

Python3

from collections import Counter
tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")
x=Counter(tuple1)
print("the element 10 occurs",x["10"],"times")

                    

Output
the element 10 occurs 3 times

Method#7: Using Countof function

Python3

tuple1=("10", "8", "5", "2", "10", "15", "10", "8", "5", "8", "8", "2")
 
import operator as op
 
print(op.countOf(tuple1,"10"))

                    

Output
3


Last Updated : 03 Nov, 2022
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