# Python | Count occurrences of an element in a Tuple

In this program, we need to accept a tuple and then find the number of times an item is present in the tuple. This can be done in various ways, but in this article, we will see how this can be done using a simple approach and how inbuilt functions can be used to solve this problem.

Examples:

`Tuple: (10, 8, 5, 2, 10, 15, 10, 8, 5, 8, 8, 2)`
```Input : 4
Output : 0 times

Input : 10
Output : 3 times

Input : 8
Output : 4 times```

Method 1(Simple Approach):

We keep a counter that keeps on increasing if the required element is found in the tuple.

## Python3

 `# Program to count the number of times an element``# Present in the list`  `def` `countX(tup, x):``    ``count ``=` `0``    ``for` `ele ``in` `tup:``        ``if` `(ele ``=``=` `x):``            ``count ``=` `count ``+` `1``    ``return` `count`  `# Driver Code``tup ``=` `(``10``, ``8``, ``5``, ``2``, ``10``, ``15``, ``10``, ``8``, ``5``, ``8``, ``8``, ``2``)``enq ``=` `4``enq1 ``=` `10``enq2 ``=` `8` `print``(countX(tup, enq))``print``(countX(tup, enq1))``print``(countX(tup, enq2))`

Output
```0
3
4```

Method 2(Using count()):

The idea is to use method count() to count number of occurrences.

## Python3

 `# Program to count the number of times an element``# Present in the list``# Count function is used`  `def` `Count(tup, en):``    ``return` `tup.count(en)`  `# Driver Code``tup ``=` `(``10``, ``8``, ``5``, ``2``, ``10``, ``15``, ``10``, ``8``, ``5``, ``8``, ``8``, ``2``)``enq ``=` `4``enq1 ``=` `10``enq2 ``=` `8``print``(Count(tup, enq), ``"times"``)``print``(Count(tup, enq1), ``"times"``)``print``(Count(tup, enq2), ``"times"``)`

Output
```0 times
3 times
4 times```

Method 3: Using list comprehension

## Python3

 `tuple1 ``=` `(``10``, ``8``, ``5``, ``2``, ``10``, ``15``, ``10``, ``8``, ``5``, ``8``, ``8``, ``2``)``x ``=` `[i ``for` `i ``in` `tuple1 ``if` `i ``=``=` `10``]``print``(``"the element 10 occurs"``, ``len``(x), ``"times"``)`

Output
```the element 10 occurs 3 times
```

Method #4: Using enumerate function

## Python3

 `tuple1``=``(``10``, ``8``, ``5``, ``2``, ``10``, ``15``, ``10``, ``8``, ``5``, ``8``, ``8``, ``2``)``x``=``[i ``for` `a,i ``in` `enumerate``(tuple1) ``if` `i``=``=``10``] ``print``(``"the element 10 occurs"``,``len``(x),``"times"``)`

Output
```the element 10 occurs 3 times
```

Method #5: Using lambda function

## Python3

 `tuple1``=``(``10``, ``8``, ``5``, ``2``, ``10``, ``15``, ``10``, ``8``, ``5``, ``8``, ``8``, ``2``)``x``=``list``(``filter``(``lambda` `i: (i``=``=``10``),tuple1))``print``(``"the element 10 occurs"``,``len``(x),``"times"``)`

Output
```the element 10 occurs 3 times
```

Method #6: Using counter function

## Python3

 `from` `collections ``import` `Counter``tuple1``=``(``"10"``, ``"8"``, ``"5"``, ``"2"``, ``"10"``, ``"15"``, ``"10"``, ``"8"``, ``"5"``, ``"8"``, ``"8"``, ``"2"``) ``x``=``Counter(tuple1) ``print``(``"the element 10 occurs"``,x[``"10"``],``"times"``)`

Output
```the element 10 occurs 3 times
```

Method#7: Using Countof function

## Python3

 `tuple1``=``(``"10"``, ``"8"``, ``"5"``, ``"2"``, ``"10"``, ``"15"``, ``"10"``, ``"8"``, ``"5"``, ``"8"``, ``"8"``, ``"2"``) ` `import` `operator as op` `print``(op.countOf(tuple1,``"10"``))`

Output
`3`

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