# Python | Convert list elements to bi-tuples

• Last Updated : 25 Nov, 2022

Sometimes, while working with Python lists, we can have a subproblem in which we need to tie a particular element with each of the list elements. This task can have its utility in the web development domain while working with queries and filters. Let’s discuss ways to solve this problem.

Method 1: Using zip() + repeat() This problem can be solved using zip() which can be used to attach to each list element with a decided number using repeat().

## Python3

 `# Python3 code to demonstrate working of``# Convert list elements to bi-tuples``# using zip() + repeat()``from` `itertools ``import` `repeat` `# initialize list``test_list ``=` `[``5``, ``6``, ``7``, ``8``, ``4``, ``3``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initialize attach element``ele ``=` `'gfg'` `# Convert list elements to bi-tuples``# using zip() + repeat()``res ``=` `list``(``zip``(test_list, repeat(ele)))` `# printing result``print``(``"Tuple list after attaching element : "` `+` `str``(res))`

Output

```The original list is : [5, 6, 7, 8, 4, 3]
Tuple list after attaching element : [(5, 'gfg'), (6, 'gfg'), (7, 'gfg'), (8, 'gfg'), (4, 'gfg'), (3, 'gfg')]
```

Method #2 : Using map() + lambda This is yet another way in which this task can be performed. In this, we just extend the logic of adding element to list element to all elements using map(), by feeding it with lambda function to perform computation tasks.

## Python3

 `# Python3 code to demonstrate working of``# Convert list elements to bi-tuples``# using map() + lambda``from` `itertools ``import` `repeat` `# initialize list``test_list ``=` `[``5``, ``6``, ``7``, ``8``, ``4``, ``3``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initialize attach element``ele ``=` `'gfg'` `# Convert list elements to bi-tuples``# using map() + lambda``res ``=` `list``(``map``(``lambda` `key: (key, ele), test_list))` `# printing result``print``(``"Tuple list after attaching element : "` `+` `str``(res))`

Output

```The original list is : [5, 6, 7, 8, 4, 3]
Tuple list after attaching element : [(5, 'gfg'), (6, 'gfg'), (7, 'gfg'), (8, 'gfg'), (4, 'gfg'), (3, 'gfg')]
```

Method #3: Using append() method

## Python3

 `# Python3 code to demonstrate working of``# Convert list elements to bi-tuples` `# initialize list``test_list ``=` `[``5``, ``6``, ``7``, ``8``, ``4``, ``3``]` `# printing original list``print``(``"The original list is : "` `+` `str``(test_list))` `# initialize attach element``ele ``=` `'gfg'``res ``=` `[]``# Convert list elements to bi-tuples``for` `i ``in` `test_list:``    ``res.append((i, ele))``# printing result``print``(``"Tuple list after attaching element : "` `+` `str``(res))`

Output

```The original list is : [5, 6, 7, 8, 4, 3]
Tuple list after attaching element : [(5, 'gfg'), (6, 'gfg'), (7, 'gfg'), (8, 'gfg'), (4, 'gfg'), (3, 'gfg')]
```

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