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Python | Convert list elements to bi-tuples

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  • Last Updated : 29 Oct, 2019
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Sometimes, while working with Python lists, we can have a subproblem in which we need to tie a particular element with each of the list element. This task can have it’s utility in web development domain while working with queries and filters. Let’s discuss a ways to solve this problem.

Method : Using zip() + repeat()

This problem can be solved using zip() which can be used to attach to each list element with a decided number using repeat().




# Python3 code to demonstrate working of
# Convert list elements to bi-tuples
# using zip() + repeat()
from itertools import repeat
  
# initialize list
test_list = [5, 6, 7, 8, 4, 3]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initialize attach element
ele = 'gfg'
  
# Convert list elements to bi-tuples
# using zip() + repeat()
res = list(zip(test_list, repeat(ele)))
  
# printing result
print("Tuple list after attaching element : " + str(res))

Output :

The original list is : [5, 6, 7, 8, 4, 3]
Tuple list after attaching element : [(5, ‘gfg’), (6, ‘gfg’), (7, ‘gfg’), (8, ‘gfg’), (4, ‘gfg’), (3, ‘gfg’)]

 

Method #2 : Using map() + lambda
This is yet another way in which this task can be performed. In this, we just extend the logic of adding element to list element to all elements using map(), by feeding it with lambda function to perform computation tasks.




# Python3 code to demonstrate working of
# Convert list elements to bi-tuples
# using map() + lambda
from itertools import repeat
  
# initialize list
test_list = [5, 6, 7, 8, 4, 3]
  
# printing original list
print("The original list is : " + str(test_list))
  
# initialize attach element
ele = 'gfg'
  
# Convert list elements to bi-tuples
# using map() + lambda
res = list(map(lambda key : (key, ele), test_list))
  
# printing result
print("Tuple list after attaching element : " + str(res))

Output :

The original list is : [5, 6, 7, 8, 4, 3]
Tuple list after attaching element : [(5, ‘gfg’), (6, ‘gfg’), (7, ‘gfg’), (8, ‘gfg’), (4, ‘gfg’), (3, ‘gfg’)]


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