# Python – Convert Coordinate Dictionary to Matrix

Sometimes, while working with Python Matrix, we can have problem in which we have dictionary records with key as matrix position and its value, and we wish to convert that to actual Matrix. This can have applications in many domains including competitive programming and day-day programming. Lets discuss certain ways in which this task can be performed.

Method #1 : Using loop + `max()` + list comprehension
The combination of above methods can be used to solve this problem. In this, we use max() to get the dimensions of matrix, list comprehension to create matrix and loop to assign values.

 `# Python3 code to demonstrate working of  ` `# Convert Coordinate Dictionary to Matrix ` `# Using loop + max() + list comprehension ` ` `  `# initializing dictionary ` `test_dict ``=` `{ (``0``, ``1``) : ``4``, (``2``, ``2``) : ``6``, (``3``, ``1``) : ``7``, (``1``, ``2``) : ``10``, (``3``, ``2``) : ``11``} ` ` `  `# printing original dictionary ` `print``(``"The original dictionary is : "` `+` `str``(test_dict)) ` ` `  `# Convert Coordinate Dictionary to Matrix ` `# Using loop + max() + list comprehension ` `temp_x ``=` `max``([cord[``0``] ``for` `cord ``in` `test_dict.keys()]) ` `temp_y ``=` `max``([cord[``1``] ``for` `cord ``in` `test_dict.keys()]) ` `res ``=` `[[``0``] ``*` `(temp_y ``+` `1``) ``for` `ele ``in` `range``(temp_x ``+` `1``)] ` ` `  `for` `(i, j), val ``in` `test_dict.items(): ` `    ``res[i][j] ``=` `val ` ` `  `# printing result  ` `print``(``"The dictionary after creation of Matrix : "` `+` `str``(res))  `

Output :

The original dictionary is : {(0, 1): 4, (1, 2): 10, (3, 2): 11, (3, 1): 7, (2, 2): 6}
The dictionary after creation of Matrix : [[0, 4, 0], [0, 0, 10], [0, 0, 6], [0, 7, 11]]

Method #2 : Using list comprehension
This is yet another way in which this task can be performed. This performs task similar to above function, just the difference is that it is shorthand to above method.

 `# Python3 code to demonstrate working of  ` `# Convert Coordinate Dictionary to Matrix ` `# Using list comprehension ` ` `  `# initializing dictionary ` `test_dict ``=` `{ (``0``, ``1``) : ``4``, (``2``, ``2``) : ``6``, (``3``, ``1``) : ``7``, (``1``, ``2``) : ``10``, (``3``, ``2``) : ``11``} ` ` `  `# printing original dictionary ` `print``(``"The original dictionary is : "` `+` `str``(test_dict)) ` ` `  `# Convert Coordinate Dictionary to Matrix ` `# Using list comprehension ` `temp_x, temp_y ``=` `map``(``max``, ``zip``(``*``test_dict)) ` `res ``=` `[[test_dict.get((j, i), ``0``) ``for` `i ``in` `range``(temp_y ``+` `1``)]  ` `                                  ``for` `j ``in` `range``(temp_x ``+` `1``)] ` ` `  `# printing result  ` `print``(``"The dictionary after creation of Matrix : "` `+` `str``(res))  `

Output :

The original dictionary is : {(0, 1): 4, (1, 2): 10, (3, 2): 11, (3, 1): 7, (2, 2): 6}
The dictionary after creation of Matrix : [[0, 4, 0], [0, 0, 10], [0, 0, 6], [0, 7, 11]]

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