Python | Check whether two lists follow same pattern or not
Last Updated :
17 Sep, 2019
Given two lists
and
, check if they follow the same pattern or not.
Condition for pattern matching:
- > , then >
- = , then =
- < , then < ,
for all i, j.
Example:
Input:
2 17 100
10 20 50
Output:
YES
Input:
5 7 10 33
10 50 10 45
Output:
NO
Approach:
To check if two lists follow the above pattern. Sort both lists and find the index of previous list element in the sorted list. If indices match, then pattern matched otherwise no pattern matched.
Code : Python program for checking the pattern.
a = [ 5 , 7 , 10 , 33 ]
b = [ 10 , 50 , 10 , 45 ]
aa = a.copy()
bb = b.copy()
aa.sort()
bb.sort()
for i in range ( len (a) - 1 ):
if aa[i] < aa[i + 1 ] and bb[i] < bb[i + 1 ]:
if a.index(aa[i]) = = b.index(bb[i]) and a.index(aa[i + 1 ]) = = b.index(bb[i + 1 ]):
flag = "YES"
else :
flag = "NO"
break
elif aa[i] = = aa[i + 1 ] and bb[i] = = bb[i + 1 ]:
if a.index(aa[i]) = = b.index(bb[i]) and a.index(aa[i + 1 ]) = = b.index(bb[i + 1 ]):
flag = "YES"
else :
flag = "NO"
break
else :
flag = "NO"
break
print (flag)
|
Output :
NO
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