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Python | Check if one dictionary is subset of other
• Last Updated : 26 Jul, 2019

Sometimes, while working with Python, we might have a problem in which we need to find, if a particular dictionary is a part of other i.e it is subset of other. A problem that have a huge potential in web development domain, having knowledge of solving can be useful. Let’s discuss certain ways in which this task can be performed.

Method #1 : Using `all() + items()`
This task can be performed using the combination of above two functions, in which we check for all the items of the subdict with the original dict using `all()` and fetch it’s each pair using `items()`.

 `# Python3 code to demonstrate working of``# Check if one dictionary is subset of other``# Using all() + items()`` ` `# Initialize dictionaries``test_dict1 ``=` `{``'gfg'` `: ``1``, ``'is'` `: ``2``, ``'best'` `: ``3``, ``'for'` `: ``4``, ``'CS'` `: ``5``}``test_dict2 ``=` `{``'gfg'` `: ``1``, ``'is'` `: ``2``, ``'best'` `: ``3``}`` ` `# printing original dictionaries``print``(``"The original dictionary 1 : "` `+`  `str``(test_dict1))``print``(``"The original dictionary 2 : "` `+`  `str``(test_dict2))`` ` `# Using all() + items()``# Check if one dictionary is subset of other``res ``=` `all``(test_dict1.get(key, ``None``) ``=``=` `val ``for` `key, val``                                 ``in` `test_dict2.items())``     ` `# printing result ``print``(``"Does dict2 lie in dict1 ? : "` `+` `str``(res))`
Output :

The original dictionary 1 : {‘CS’: 5, ‘is’: 2, ‘best’: 3, ‘gfg’: 1, ‘for’: 4}
The original dictionary 2 : {‘is’: 2, ‘best’: 3, ‘gfg’: 1}
Does dict2 lie in dict1 ? : True

Method #2 : Using `items() + <= operator`
Another alternative to perform the above task can be using the `items()` along with` <=` operator. This just checks for less than or all values of all the key value matched.

 `# Python3 code to demonstrate working of``# Check if one dictionary is subset of other``# Using items() + <= operator`` ` `# Initialize dictionaries``test_dict1 ``=` `{``'gfg'` `: ``1``, ``'is'` `: ``2``, ``'best'` `: ``3``, ``'for'` `: ``4``, ``'CS'` `: ``5``}``test_dict2 ``=` `{``'gfg'` `: ``1``, ``'is'` `: ``2``, ``'best'` `: ``3``}`` ` `# printing original dictionaries``print``(``"The original dictionary 1 : "` `+`  `str``(test_dict1))``print``(``"The original dictionary 2 : "` `+`  `str``(test_dict2))`` ` `# Using items() + <= operator``# Check if one dictionary is subset of other``res ``=` `test_dict2.items() <``=` `test_dict1.items()``     ` `# printing result ``print``(``"Does dict2 lie in dict1 ? : "` `+` `str``(res))`
Output :

The original dictionary 1 : {‘CS’: 5, ‘is’: 2, ‘best’: 3, ‘gfg’: 1, ‘for’: 4}
The original dictionary 2 : {‘is’: 2, ‘best’: 3, ‘gfg’: 1}
Does dict2 lie in dict1 ? : True

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