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# Python | Check if one list is subset of other

• Last Updated : 13 Sep, 2021

Sometimes we encounter the problem of checking if one list is just an extension of the list i.e just a superset of one list. This kind of problems are quite popular in competitive programming. Having shorthands for it helps the cause. Lets discuss various ways to achieve this particular task.
Method #1 : Using all()
all() is used to check all the elements of a container in just one line. Checks for all the elements of one list for existence in other list.

## Python3

 `# Python3 code to demonstrate``# to check if list is subset of other``# using all()` `# initializing list``test_list ``=` `[``9``, ``4``, ``5``, ``8``, ``10``]``sub_list ``=` `[``10``, ``5``, ``4``]` `# printing original lists``print` `(``"Original list : "` `+` `str``(test_list))``print` `(``"Original sub list : "` `+` `str``(sub_list))` `# using all() to``# check subset of list``flag ``=` `0``if``(``all``(x ``in` `test_list ``for` `x ``in` `sub_list)):``    ``flag ``=` `1``    ` `# printing result``if` `(flag) :``    ``print` `(``"Yes, list is subset of other."``)``else` `:``    ``print` `(``"No, list is not subset of other."``)`

Output :

```Original list : [9, 4, 5, 8, 10]
Original sub list : [10, 5, 4]
Yes, list is subset of other.```

Method #2 : Using set.issubset()
The most used and recommended method to check for a sublist. This function is tailor made to perform the particular task of checking if one list is a subset of another.

## Python3

 `# Python3 code to demonstrate``# to check if list is subset of other``# using issubset()` `# initializing list``test_list ``=` `[``9``, ``4``, ``5``, ``8``, ``10``]``sub_list ``=` `[``10``, ``5``]` `# printing original lists``print` `(``"Original list : "` `+` `str``(test_list))``print` `(``"Original sub list : "` `+` `str``(sub_list))` `# using issubset() to``# check subset of list``flag ``=` `0``if``(``set``(sub_list).issubset(``set``(test_list))):``    ``flag ``=` `1``    ` `# printing result``if` `(flag) :``    ``print` `(``"Yes, list is subset of other."``)``else` `:``    ``print` `(``"No, list is not subset of other."``)`

Output :

```Original list : [9, 4, 5, 8, 10]
Original sub list : [10, 5]
Yes, list is subset of other.```

Method #3 : Using set.intersection()
Yet another method dealing with sets, this method checks if the intersection of both the lists ends up to be the sub list we are checking. This confirms that one list is a subset of the other.

## Python3

 `# Python3 code to demonstrate``# to check if list is subset of other``# using intersection()` `# initializing list``test_list ``=` `[``9``, ``4``, ``5``, ``8``, ``10``]``sub_list ``=` `[``10``, ``5``]` `# printing original lists``print` `(``"Original list : "` `+` `str``(test_list))``print` `(``"Original sub list : "` `+` `str``(sub_list))` `# using intersection() to``# check subset of list``flag ``=` `0``if``((``set``(sub_list) & ``set``(test_list))``=``=` `set``(sub_list)):``    ``flag ``=` `1``    ` `# printing result``if` `(flag) :``    ``print` `(``"Yes, list is subset of other."``)``else` `:``    ``print` `(``"No, list is not subset of other."``)`

Output :

```Original list : [9, 4, 5, 8, 10]
Original sub list : [10, 5]
Yes, list is subset of other.```

Method #4 : Using iteration and counter
Using count of element in both lists to check whether the second list is a subset of the first list.

## Python3

 `# Python3 code to demonstrate``# to check if list is subset of other` `#Importing``from` `collections ``import` `Counter` `def` `checkInFirst(a, b):``     ``#getting count``    ``count_a ``=` `Counter(a)``    ``count_b ``=` `Counter(b)` `    ``#checking if element exists in second list``    ``for` `key ``in` `count_b:``        ``if` `key ``not` `in`  `count_a:``            ``return` `False``        ``if` `count_b[key] > count_b[key]:``            ``return` `False``    ``return` `True` `# initializing list``a ``=` `[``1``, ``2``,``4``,``5``]``b ``=` `[``1``, ``2``,``3``]` `#Calling function``res ``=` `checkInFirst(a, b)` `#Printing list``print` `(``"Original list : "` `+` `str``(a))``print` `(``"Original sub list : "` `+` `str``(b))` `if` `res``=``=``True` `:``    ``print` `(``"Yes, list is subset of other."``)``else` `:``    ``print` `(``"No, list is not subset of other."``)``    ` `#Added by Paras Jain(everythingispossible)`

Output :

```Original list : [1, 2, 4, 5]
Original sub list : [1, 2, 3]
No, list is not subset of other.```

Method #5 : Using set index

## Python3

 `# Python3 code to demonstrate``# to check if list is subset of other` `# initializing list``one ``=` `[``1``,``2``,``3``,``4``,``5``]``two ``=` `[``1``,``2``]` `#using set to find if element exists in another list``result ``=` `set``(x ``in` `one ``for` `x ``in` `two)` `flag ``=` `0` `for` `ans ``in` `result:``    ``if` `ans ``=``=` `False``:``        ``flag``=``1` `#Printing list``print` `(``"Original list : "` `+` `str``(one))``print` `(``"Original sub list : "` `+` `str``(two))` `if` `flag``=``=``0``:``    ``print``(``"Yes, list is subset of other."``)``else``:``    ``print``(``"No, list is not subset of other."``)` `#Added by Paras Jain(everythingispossible)`

Output :

```Original list : [1, 2, 3, 4, 5]
Original sub list : [1, 2]
Yes, list is subset of other.```

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