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# Python | Categorize the given list by string size

• Last Updated : 01 May, 2019

Sometimes, we have a use case in which we need to perform the grouping of strings by various factors, like first letter or any other factor. These type of problems are typical to database queries and hence can occur in web development while programming. This article focuses on one such grouping by size of string. Let’s discuss certain ways in which this can be performed.

Method #1 : Using `next()` + lambda + loop

The combination of above 3 functions is used to solve this particular problem by the naive method. The lambda function performs the task of finding like lengths, and next function helps in forward iteration.

 `# Python3 code to demonstrate``# Categorize by string size ``# using next() + lambda + loop`` ` `# initializing list``test_list ``=` `[``'man'``, ``'a'``, ``'geek'``, ``'for'``, ``'b'``, ``'free'``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using next() + lambda + loop``# Categorize by string size ``util_func ``=` `lambda` `x, y: ``len``(x) ``=``=` `len``(y)``res ``=` `[]``for` `sub ``in` `test_list:``    ``ele ``=` `next``((x ``for` `x ``in` `res ``if` `util_func(sub, x[``0``])), [])``    ``if` `ele ``=``=` `[]:``        ``res.append(ele)``    ``ele.append(sub)`` ` `# print result``print``(``"The list after Categorization : "` `+` `str``(res))`
Output :
```The original list : ['man', 'a', 'geek', 'for', 'b', 'free']
The list after Categorization : [['man', 'for'], ['a', 'b'], ['geek', 'free']]
```

Method #2 : Using `sorted() + groupby()`

This particular task can also be solved using the groupby function which offers a convenient method to solve this problem. The sorted function sorts the elements by size to be feed to groupby for the relevant grouping.

 `# Python3 code to demonstrate``# Categorize by string size ``# using sorted() + groupby()``from` `itertools ``import` `groupby`` ` `# initializing list``test_list ``=` `[``'man'``, ``'a'``, ``'geek'``, ``'for'``, ``'b'``, ``'free'``]`` ` `# printing original list``print``(``"The original list : "` `+` `str``(test_list))`` ` `# using sorted() + groupby()``# Categorize by string size ``util_func ``=` `lambda` `x: ``len``(x)``temp ``=` `sorted``(test_list, key ``=` `util_func)``res ``=` `[``list``(ele) ``for` `i, ele ``in` `groupby(temp, util_func)]`` ` `# print result``print``(``"The list after Categorization : "` `+` `str``(res))`
Output :
```The original list : ['man', 'a', 'geek', 'for', 'b', 'free']
The list after Categorization : [['a', 'b'], ['man', 'for'], ['geek', 'free']]
```

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