Python – Assign Alphabet to each element

Given a list of elements, assign similar alphabet to same element.

Input : test_list = [4, 5, 2, 4, 2, 6]
Output : [‘a’, ‘b’, ‘c’, ‘a’, ‘c’, ‘d’]
Explanation : Alphabets assigned to elements as occurring.

Input : test_list = [4, 5, 2, 4, 2, 6]
Output : [‘a’, ‘b’, ‘c’, ‘a’, ‘c’]
Explanation : Alphabets assigned to elements as occurring.

Method #1 : Using ascii_lowecase() + loop + list comprehension 

In this, we extract all lowercase alphabets using lowercase(), and create dictionary mapping same element to similar character, post that we flatten that to appropriate index using list comprehension.



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# Python3 code to demonstrate working of 
# Assign Alphabet to each element
# Using ascii_lowecase() + loop + list comprehension
import string
  
# initializing list
test_list = [4, 5, 2, 4, 2, 6, 5, 2, 5]
  
# printing list
print("The original list : " + str(test_list))
  
temp = {}
cntr = 0
for ele in test_list:
    if ele in temp:
        continue
      
    # assiging same Alphabet to same element
    temp[ele] = string.ascii_lowercase[cntr]
    cntr += 1
      
# flattening 
res = [temp.get(ele) for ele in test_list]
  
# printing results 
print("The mapped List : " + str(res))

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Output


The original list : [4, 5, 2, 4, 2, 6, 5, 2, 5]
The mapped List : ['a', 'b', 'c', 'a', 'c', 'd', 'b', 'c', 'b']





Method #2 : Using defaultdict() + ascii_lowercase() + iter()


In this we use defaultdict() to assign values to similar elements, ascii_lowercase() is used to get all lowercase all lowercased alphabets.




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# Python3 code to demonstrate working of  


# Assign Alphabet to each element 


# Using defaultdict() + ascii_lowercase() + iter() 


from collections import defaultdict 


import string  


  


# initializing list 


test_list = [4, 5, 2, 4, 2, 6, 5, 2, 5] 


  


# printing list 


print("The original list : " + str(test_list)) 


  


# assigning lowecases as iterator 


temp = iter(string.ascii_lowercase) 


  


# lambda functions fits to similar elements  


res = defaultdict(lambda: next(temp)) 


  


# flatten in list  


res = [res[key] for key in test_list] 


  


# printing results  


print("The mapped List : " + str(list(res))) 



















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Output


The original list : [4, 5, 2, 4, 2, 6, 5, 2, 5]
The mapped List : ['a', 'b', 'c', 'a', 'c', 'd', 'b', 'c', 'b']







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