PyQt5 QSpinBox – Finding child using ID
In this article we will see how we can find the child of spin box using the child ID, we can get the child id using winId method with the object of child. Spin box is the parent widget it has child like line edit widget and those up and down button.
In order to do this we use find method
Syntax : spin_box.find(id)
Argument : It takes child id as argument
Return : It returns the child object
Below is the implementation
# importing librariesfrom PyQt5.QtWidgets import * from PyQt5 import QtCore, QtGuifrom PyQt5.QtGui import * from PyQt5.QtCore import * import sys class Window(QMainWindow): def __init__(self): super().__init__() # setting title self.setWindowTitle("Python ") # setting geometry self.setGeometry(100, 100, 600, 400) # calling method self.UiComponents() # showing all the widgets self.show() # method for widgets def UiComponents(self): # creating spin box self.spin = QSpinBox(self) # setting geometry to spin box self.spin.setGeometry(100, 100, 250, 40) # setting range to the spin box self.spin.setRange(0, 999999) # setting prefix to spin self.spin.setPrefix("Prefix ") # setting suffix to spin self.spin.setSuffix(" Suffix") # ensuring spin box is polished i_d = self.spin.lineEdit().winId() # getting child using ID child = self.spin.find(i_d) # creating a label label = QLabel(self) # making it multi line label.setWordWrap(True) # setting its geometry label.setGeometry(100, 200, 200, 60) # setting text to the label label.setText(str(child)) # create pyqt5 appApp = QApplication(sys.argv) # create the instance of our Windowwindow = Window() # start the appsys.exit(App.exec()) |
Output :
