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PyQt5 QSpinBox – Checking if it is visible using isVisible
  • Last Updated : 17 May, 2020

In this article we will see how we can check if the spin box visible with the help of isVisible method. We can hide the spin box using hide method or setHidden method. By default spin box is visible.

Note : If we use this method inside the window class it will return false as the window is created at that time and it didn’t know if it is visible or not therefore it is used outside the class

In order to do so we use isVisible method.

Syntax : classs_object.spin_box.isVisible()

Argument : It takes no argument



Return : It returns bool

Below is the implementation




# importing libraries
from PyQt5.QtWidgets import * 
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import * 
from PyQt5.QtCore import * 
import sys
  
class Window(QMainWindow):
  
    def __init__(self):
        super().__init__()
  
        # setting title
        self.setWindowTitle("Python ")
  
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
  
        # calling method
        self.UiComponents()
  
        # showing all the widgets
        self.show()
  
    # method for widgets
    def UiComponents(self):
  
        # creating spin box
        self.spin = QSpinBox(self)
  
        # setting geometry to spin box
        self.spin.setGeometry(100, 100, 250, 40)
  
        # setting prefix to spin
        self.spin.setPrefix("Prefix ")
  
        # setting suffix to spin
        self.spin.setSuffix(" Suffix")
  
  
# create pyqt5 app
App = QApplication(sys.argv)
  
# create the instance of our Window
window = Window()
  
# checking if the spin box was visible
check = window.spin.isVisible()
  
# printing the status
print(check)
  
# start the app
sys.exit(App.exec())

Output :

True

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