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PyQt5 QLabel – Checking if the color effect is disabled or not

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In this article we will see how we can check if the color effect of the label is disabled or not. In order to make the color effect disable we use setEnabled method. In order to check the color effect is disable and enable we use isEnabled method.

Syntax : color_effect.isEnabled() Argument : It takes no argument Return : It returns bool

Below is the implementation 

Python3

# importing libraries
from PyQt5.QtWidgets import *
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import *
from PyQt5.QtCore import *
import sys
 
 
class Window(QMainWindow):
 
    def __init__(self):
        super().__init__()
 
        # making background color light yellow
        self.setStyleSheet("background : lightyellow;")
 
        # setting title
        self.setWindowTitle("Python ")
 
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
 
        # calling method
        self.UiComponents()
 
        # showing all the widgets
        self.show()
 
    # method for widgets
    def UiComponents(self):
 
        # creating label
        label = QLabel("Label", self)
 
        # setting geometry to the label
        label.setGeometry(200, 100, 150, 60)
 
        # setting alignment to the label
        label.setAlignment(Qt.AlignCenter)
 
        # setting font
        label.setFont(QFont('Arial', 15))
 
        # creating a color effect
        self.color_effect = QGraphicsColorizeEffect()
 
        # setting color to color effect
        self.color_effect.setColor(Qt.darkBlue)
 
        # adding color effect to the label
        label.setGraphicsEffect(self.color_effect)
 
        # creating result label
        result = QLabel(self)
 
        # setting geometry to the result
        result.setGeometry(200, 200, 300, 30)
 
        # checking if color effect is enabled
        check = self.color_effect.isEnabled()
 
        # setting text to result label
        result.setText("Enabled ? : " + str(check))
 
 
# create pyqt5 app
App = QApplication(sys.argv)
 
# create the instance of our Window
window = Window()
 
# start the app
sys.exit(App.exec())

                    

Output :



Last Updated : 30 Jan, 2023
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