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PyQt5 – Background image of checked RadioButton indicator when pressed

  • Last Updated : 22 Apr, 2020

In this article we will see how we can set background image to the indicator of radio button when it get pressed and was in checked state. By default when we press the radio button there is bluish color associated with it although we can change it. The background image only appear to the indicator when it was in checked state and when we press the radio button.

In order to add background image to indicator of radio button we have to change the style sheet code of it. Below is the style sheet code.

QRadioButton::indicator:checked:pressed
{
background-image : url(image.png);
}

Below is the implementation.




# importing libraries
from PyQt5.QtWidgets import * 
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import * 
from PyQt5.QtCore import * 
import sys
  
  
class Window(QMainWindow):
  
    def __init__(self):
        super().__init__()
  
        # setting title
        self.setWindowTitle("Python ")
  
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
  
        # calling method
        self.UiComponents()
  
        # showing all the widgets
        self.show()
  
    # method for widgets
    def UiComponents(self):
        # creating a radio button
        self.radio_button = QRadioButton(self)
  
        # setting geometry of radio button
        self.radio_button.setGeometry(200, 150, 120, 40)
  
        # setting text to radio button
        self.radio_button.setText("Radio Button")
  
        # changing style sheet code of radio button
        # setting background image checked indicator when it get pressed
        self.radio_button.setStyleSheet("QRadioButton::indicator:checked:pressed"
                                        "{"
                                        "background-image : url(image.png);"
                                        "}")
  
  
# create pyqt5 app
App = QApplication(sys.argv)
  
# create the instance of our Window
window = Window()
  
# start the app
sys.exit(App.exec())

Output :

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