Open In App

PyQt5 – Background image to pressed indicator when pressed from checked state | Check Box

Last Updated : 22 Apr, 2020
Improve
Improve
Like Article
Like
Save
Share
Report

In this article we will see how to add background image to the pressed indicator which was initially in the checked state. In order to do this we have to change the style sheet code associated with the check box object and have to add background image to the indicator of checked state when it get pressed.

Below is the style sheet code.

QCheckBox::indicator:checked:pressed
{
background-image : url(image.png);
}

Below is the implementation.




# importing libraries
from PyQt5.QtWidgets import * 
from PyQt5 import QtCore, QtGui
from PyQt5.QtGui import * 
from PyQt5.QtCore import * 
import sys
  
  
class Window(QMainWindow):
  
    def __init__(self):
        super().__init__()
  
        # setting title
        self.setWindowTitle("Python ")
  
        # setting geometry
        self.setGeometry(100, 100, 600, 400)
  
        # calling method
        self.UiComponents()
  
        # showing all the widgets
        self.show()
  
    # method for widgets
    def UiComponents(self):
        # creating the check-box
        checkbox = QCheckBox('Geek ?', self)
  
        # setting geometry of check box
        checkbox.setGeometry(200, 150, 100, 60)
  
        # changing size of indicator
        # adding background image to the pressed indicator
        # when it is in checked state
        checkbox.setStyleSheet("QCheckBox::indicator"
                               "{"
                               "width : 60px;"
                               "height : 60px;"
                               "}"
                               "QCheckBox::indicator:checked:pressed"
                               "{"
                               "background-image : url(indicator_image.png);"
                               "}")
  
  
# create pyqt5 app
App = QApplication(sys.argv)
  
# create the instance of our Window
window = Window()
  
# start the app
sys.exit(App.exec())


Output :



Like Article
Suggest improvement
Previous
Next
Share your thoughts in the comments

Similar Reads