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Program to convert Java Set to Sequence in Scala

Last Updated : 29 Nov, 2019
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A java Set can be converted to a Sequence in Scala by utilizing toSeq method of Java in Scala. Here, we need to import Scala’s JavaConversions object in order to make this conversions work.
Now, lets see some examples and then discuss how it works in details.
Example:1#




// Scala program to convert Java set 
// to Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding integers to the set
        set.add(9)
        set.add(10)
        set.add(11)
          
        // Converting set to Sequence 
        val seq = set.toSeq
          
        // Displays Sequence 
        println(seq)
          
    }
}


Output:

ArrayBuffer(9, 10, 11)

Therefore, a Sequence of integers is returned. Here, firstly a set is created where, integer elements are added to it utilizing add method. After that toSeq method is utilized in order to convert the stated set to a Sequence.
Example:2#




// Scala program to convert Java set 
// to a Sequence in Scala
  
// Importing Scala's JavaConversions object
import scala.collection.JavaConversions._
  
  
// Creating object
object GfG
  
    // Main method
    def main(args:Array[String])
    {
      
        // Creating set in Java
        val set = new java.util.HashSet[Int]()
          
        // Adding Integers to the set
        set.add(2)
        set.add(1)
        set.add(3)
          
        // Converting set to a Sequence
        val seq = set.toSeq
          
        // Displays Sequence
        println(seq)
      
    }
}


Output:

ArrayBuffer(1, 2, 3)

It is same as above example but here the elements of the set are not present in a proper order. But the Sequence returned is in proper order.



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