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How will you print numbers from 1 to 100 without using loop? | Set-2
  • Difficulty Level : Easy
  • Last Updated : 02 Jun, 2020

If we take a look at this problem carefully, we can see that the idea of “loop” is to track some counter value e.g. “i=0” till “i <= 100". So if we aren't allowed to use loop, how else can be track something in C language!

It can be done in many ways to print numbers using any looping conditions such as for(), while(), do-while(). But the same can be done without using loops (using recursive functions, goto statement).

Printing numbers from 1 to 100 using recursive functions has already been discussed in Set-1 . In this post, other two methods have been discussed:

  1. Using goto statement:

    C++

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    #include <iostream>
    using namespace std;
      
    int main()
    {
        int i = 0;
          
    begin:
        i = i + 1;
        cout << i << " ";
      
        if (i < 100)
        {
            goto begin;
        }
        return 0;
    }
      
    // This code is contributed by ShubhamCoder

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    C

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    #include <stdio.h>
      
    int main()
    {
        int i = 0;
    begin:
        i = i + 1;
        printf("%d ", i);
      
        if (i < 100)
            goto begin;
        return 0;
    }

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    C#

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    using System;
      
    class GFG{
      
    static public void Main ()
    {
        int i = 0;
        begin:
            i = i + 1;
            Console.Write(" " + i + " ");
      
            if (i < 100)
            {
                goto begin;
            }
    }
    }
      
    // This code is contributed by ShubhamCoder

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    Output:

    1 2 3 4 . . . 97 98 99 100
    
  2. Using recursive main function:

    C++

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    #include <iostream>
    using namespace std;
      
    int main()
    {
        static int i = 1;
          
        if (i <= 100)
        {
            cout << i++ << " ";
            main();
        }
        return 0;
    }
      
    // This code is contributed by ShubhamCoder

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    C

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    #include <stdio.h>
      
    int main()
    {
        static int i = 1;
        if (i <= 100) {
            printf("%d ", i++);
            main();
        }
        return 0;
    }

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    Java

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    // Java program to count all pairs from both the
    // linked lists whose product is equal to
    // a given value
    class GFG 
    {
        static int i = 1;
      
        public static void main(String[] args) 
        {
      
            if (i <= 100)
            {
                System.out.printf("%d ", i++);
                main(null);
            }
        }
    }
      
    // This code is contributed by Rajput-Ji

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    C#

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    // C# program to count all pairs from both the
    // linked lists whose product is equal to
    // a given value
    using System;
      
    class GFG 
    {
        static int i = 1;
      
        public static void Main(String[] args) 
        {
            if (i <= 100)
            {
                Console.Write("{0} ", i++);
                Main(null);
            }
        }
    }
      
    // This code is contributed by Rajput-Ji

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    Output:

    1 2 3 4 . . . 97 98 99 100
    

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