Given a point (x1, y1) and a line (ax + by + c = 0). The task is to find the perpendicular distance between the given point and the line.

**Examples :**

Input:x1 = 5, y1 = 6, a = -2, b = 3, c = 4Output:3.32820117735Input:x1 = -1, y1 = 3, a = 4, b = -3, c = – 5Output:3.6

**Approach: **The distance (i.e shortest distance) from a given point to a line is the perpendicular distance from that point to the given line. The equation of a line in the plane is given by the equation ax + by + c = 0, where a, b and c are real constants. the co-ordinate of the point is (x1, y1)

The formula for distance between a point and a line in 2-D is given by:

Distance = (| a*x1 + b*y1 + c |) / (sqrt( a*a + b*b))

Below is the implementation of the above formulae: **Program 1:**

## C

`// C program to find the distance` `// between a given point and a` `// given line in 2 D.` `#include<stdio.h>` `#include<math.h>` `// Function to find distance` `void` `shortest_distance(` `float` `x1, ` `float` `y1,` ` ` `float` `a, ` `float` `b,` ` ` `float` `c)` `{` ` ` `float` `d = ` `fabs` `((a * x1 + b * y1 + c)) /` ` ` `(` `sqrt` `(a * a + b * b));` ` ` `printf` `(` `"Perpendicular distance is %f\n"` `, d);` ` ` `return` `;` `}` `// Driver Code` `int` `main()` `{` ` ` `float` `x1 = 5;` ` ` `float` `y1 = 6;` ` ` `float` `a = -2;` ` ` `float` `b = 3;` ` ` `float` `c = 4;` ` ` `shortest_distance(x1, y1, a, b, c);` ` ` `return` `0;` `}` `// This code is contributed` `// by Amber_Saxena.` |

## Java

`// Java program to find` `// the distance between` `// a given point and a` `// given line in 2 D.` `import` `java.io.*;` `class` `GFG` `{` ` ` ` ` `// Function to find distance` ` ` `static` `void` `shortest_distance(` `float` `x1, ` `float` `y1,` ` ` `float` `a, ` `float` `b,` ` ` `float` `c)` ` ` `{` ` ` `double` `d = Math.abs(((a * x1 + b * y1 + c)) /` ` ` `(Math.sqrt(a * a + b * b)));` ` ` `System.out.println(` `"Perpendicular "` `+` ` ` `"distance is "` `+ d);` ` ` `return` `;` ` ` `}` ` ` `// Driver code` ` ` `public` `static` `void` `main (String[] args)` ` ` `{` ` ` `float` `x1 = ` `5` `;` ` ` `float` `y1 = ` `6` `;` ` ` `float` `a = -` `2` `;` ` ` `float` `b = ` `3` `;` ` ` `float` `c = ` `4` `;` ` ` `shortest_distance(x1, y1, a, b, c);` ` ` `}` `}` `// This code is contributed` `// by Mahadev.` |

## Python

`# Python program to find the distance between` `# a given point and a given line in 2 D.` `import` `math` `# Function to find distance` `def` `shortest_distance(x1, y1, a, b, c):` ` ` ` ` `d ` `=` `abs` `((a ` `*` `x1 ` `+` `b ` `*` `y1 ` `+` `c)) ` `/` `(math.sqrt(a ` `*` `a ` `+` `b ` `*` `b))` ` ` `print` `(` `"Perpendicular distance is"` `),d` ` ` `# Driver Code` `x1 ` `=` `5` `y1 ` `=` `6` `a ` `=` `-` `2` `b ` `=` `3` `c ` `=` `4` `shortest_distance(x1, y1, a, b, c) ` |

## C#

`// C# program to find` `// the distance between` `// a given point and a` `// given line in 2 D.` `using` `System;` `class` `GFG` `{` ` ` ` ` `// Function to find distance` ` ` `static` `void` `shortest_distance(` `float` `x1, ` `float` `y1,` ` ` `float` `a, ` `float` `b,` ` ` `float` `c)` ` ` `{` ` ` `double` `d = Math.Abs(((a * x1 + b * y1 + c)) /` ` ` `(Math.Sqrt(a * a + b * b)));` ` ` `Console.WriteLine(` `"Perpendicular "` `+` ` ` `"distance is "` `+ d);` ` ` `return` `;` ` ` `}` ` ` `// Driver code` ` ` `public` `static` `void` `Main ()` ` ` `{` ` ` `float` `x1 = 5;` ` ` `float` `y1 = 6;` ` ` `float` `a = -2;` ` ` `float` `b = 3;` ` ` `float` `c = 4;` ` ` `shortest_distance(x1, y1, a, b, c);` ` ` `}` `}` `// This code is contributed` `// by inder_verma..` |

## PHP

`<?php` `// PHP program to find the distance` `// between a given point and a` `// given line in 2 D.` `// Function to find distance` `function` `shortest_distance(` `$x1` `, ` `$y1` `, ` `$a` `, ` `$b` `, ` `$c` `)` `{` ` ` `$d` `= ` `abs` `((` `$a` `* ` `$x1` `+ ` `$b` `* ` `$y1` `+ ` `$c` `)) /` ` ` `(sqrt(` `$a` `* ` `$a` `+ ` `$b` `* ` `$b` `));` ` ` `echo` `"Perpendicular distance is "` `, ` `$d` `;` `}` `// Driver Code` `$x1` `= 5;` `$y1` `= 6;` `$a` `= -2;` `$b` `= 3;` `$c` `= 4;` `shortest_distance(` `$x1` `, ` `$y1` `, ` `$a` `, ` `$b` `, ` `$c` `);` `// This code is contributed` `// by inder_verma..` `?>` |

## Javascript

`<script>` `// Javascript program to find` `// the distance between` `// a given povar and a` `// given line in 2 D.` ` ` `// Function to find distance` ` ` `function` `shortest_distance(x1 , y1 , a , b , c)` ` ` `{` ` ` `var` `d = Math.abs((` ` ` `(a * x1 + b * y1 + c)) / (Math.sqrt(a * a + b * b)));` ` ` `document.write(` `"Perpendicular "` `+` ` ` `"distance is "` `+ d.toFixed(11));` ` ` `return` `;` ` ` `}` ` ` `// Driver code` ` ` ` ` `var` `x1 = 5;` ` ` `var` `y1 = 6;` ` ` `var` `a = -2;` ` ` `var` `b = 3;` ` ` `var` `c = 4;` ` ` `shortest_distance(x1, y1, a, b, c);` `// This code is contributed by todaysgaurav` `</script>` |

**Output:**

Perpendicular distance is 3.32820117735

**Program 2**:

## C

`// C program to find the distance` `// between a given point and a` `// given line in 2 D.` `#include<stdio.h>` `#include<math.h>` `// Function to find distance` `void` `shortest_distance(` `float` `x1, ` `float` `y1,` ` ` `float` `a, ` `float` `b,` ` ` `float` `c)` `{` ` ` `float` `d = ` `fabs` `((a * x1 + b * y1 + c)) /` ` ` `(` `sqrt` `(a * a + b * b));` ` ` `printf` `(` `"Perpendicular distance is %f\n"` `, d);` ` ` `return` `;` `}` `// Driver Code` `int` `main()` `{` ` ` `float` `x1 = -1;` ` ` `float` `y1 = 3;` ` ` `float` `a = 4;` ` ` `float` `b = -3;` ` ` `float` `c = - 5;` ` ` `shortest_distance(x1, y1, a, b, c);` ` ` `return` `0;` `}` `// This code is contributed` `// by Amber_Saxena.` |

## Java

`// Java program to find the distance` `// between a given point and a` `// given line in 2 D.` `class` `GFG` `{` `// Function to find distance` `static` `void` `shortest_distance(` `double` `x1, ` `double` `y1,` ` ` `double` `a, ` `double` `b,` ` ` `double` `c)` `{` ` ` `double` `d = Math.abs((a * x1 + b * y1 + c)) /` ` ` `(Math.sqrt(a * a + b * b));` ` ` `System.out.println(` `"Perpendicular distance is "` `+ d);` ` ` `return` `;` `}` `// Driver Code` `public` `static` `void` `main(String[] args)` `{` ` ` `double` `x1 = -` `1` `;` ` ` `double` `y1 = ` `3` `;` ` ` `double` `a = ` `4` `;` ` ` `double` `b = -` `3` `;` ` ` `double` `c = - ` `5` `;` ` ` `shortest_distance(x1, y1, a, b, c);` `}` `}` `// This code is contributed` `// by mits` |

## Python

`# Python program to find the distance between` `# a given point and a given line in 2 D.` `import` `math` `# Function to find distance` `def` `shortest_distance(x1, y1, a, b, c):` ` ` ` ` `d ` `=` `abs` `((a ` `*` `x1 ` `+` `b ` `*` `y1 ` `+` `c)) ` `/` `(math.sqrt(a ` `*` `a ` `+` `b ` `*` `b))` ` ` `print` `(` `"Perpendicular distance is"` `),d` ` ` `# Driver Code` `x1 ` `=` `-` `1` `y1 ` `=` `3` `a ` `=` `4` `b ` `=` `-` `3` `c ` `=` `-` `5` `shortest_distance(x1, y1, a, b, c) ` |

## C#

`// C# program to find the distance` `// between a given point and a` `// given line in 2 D.` `using` `System;` `class` `GFG` `{` `// Function to find distance` `static` `void` `shortest_distance(` `double` `x1, ` `double` `y1,` ` ` `double` `a, ` `double` `b,` ` ` `double` `c)` `{` ` ` `double` `d = Math.Abs((a * x1 + b * y1 + c)) /` ` ` `(Math.Sqrt(a * a + b * b));` ` ` `Console.WriteLine(` `"Perpendicular distance is "` `+ d);` ` ` `return` `;` `}` `// Driver Code` `public` `static` `void` `Main()` `{` ` ` `double` `x1 = -1;` ` ` `double` `y1 = 3;` ` ` `double` `a = 4;` ` ` `double` `b = -3;` ` ` `double` `c = - 5;` ` ` `shortest_distance(x1, y1, a, b, c);` `}` `}` `// This code is contributed` `// by Akanksha Rai` |

## PHP

`<?php` `// PHP program to find the distance` `// between a given point and a` `// given line in 2 D.` `// Function to find distance` `function` `shortest_distance(` `$x1` `, ` `$y1` `, ` `$a` `,` ` ` `$b` `, ` `$c` `)` `{` ` ` `$d` `= ` `abs` `((int)(` `$a` `* ` `$x1` `+ ` `$b` `* ` `$y1` `+ ` `$c` `) /` ` ` `sqrt(` `$a` `* ` `$a` `+ ` `$b` `* ` `$b` `));` ` ` `echo` `"Perpendicular distance is "` `, ` `$d` `;` `}` `// Driver Code` `$x1` `= -1;` `$y1` `= 3;` `$a` `= 4;` `$b` `= -3;` `$c` `= -5;` `shortest_distance(` `$x1` `, ` `$y1` `, ` `$a` `, ` `$b` `, ` `$c` `);` `// This code is contributed` `// by inder_verma..` `?>` |

## Javascript

`<script>` `// Javascript program to find the distance` `// between a given point and a` `// given line in 2 D.` `// Function to find distance` `function` `shortest_distance(x1, y1, a, b, c)` `{` ` ` `let d = Math.abs((a * x1 + b * y1 + c)) /` ` ` `(Math.sqrt(a * a + b * b));` ` ` `document.write(` `"Perpendicular distance is "` `+ d);` ` ` `return` `;` `}` ` ` `// driver program` ` ` `let x1 = -1;` ` ` `let y1 = 3;` ` ` `let a = 4;` ` ` `let b = -3;` ` ` `let c = - 5;` ` ` `shortest_distance(x1, y1, a, b, c);` ` ` ` ` `// This code is contributed by susmitakundugoaldanga.` `</script>` |

**Output:**

Perpendicular distance is 3.6

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