# Permutations of a given string using STL

A permutation, also called an “arrangement number” or “order”, is a rearrangement of the elements of an ordered list S into a one-to-one correspondence with S itself. A string of length n has n! permutation.

Source: Mathword

Below are the permutations of string ABC.

ABC ACB BAC BCA CBA CAB

We have discussed C implementation to print all permutations of a given string using backtracking here. In this post, C++ implementation using STL is discussed.

**Method 1 (Using rotate())**

std::rotate function rotates elements of a vector/string such that the passed middle element becomes first. For example, if we call rotate for “ABCD” with middle as second element, the string becomes “BCDA” and if we again call rotate with middle as second element, the string becomes “CDAB”. Refer this for a sample program.

Below is C++ implementation.

`// C++ program to print all permutations with ` `// duplicates allowed using rotate() in STL ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to print permutations of string str, ` `// out is used to store permutations one by one ` `void` `permute(string str, string out) ` `{ ` ` ` `// When size of str becomes 0, out has a ` ` ` `// permutation (length of out is n) ` ` ` `if` `(str.size() == 0) ` ` ` `{ ` ` ` `cout << out << endl; ` ` ` `return` `; ` ` ` `} ` ` ` ` ` `// One be one move all characters at ` ` ` `// the beginning of out (or result) ` ` ` `for` `(` `int` `i = 0; i < str.size(); i++) ` ` ` `{ ` ` ` `// Remove first character from str and ` ` ` `// add it to out ` ` ` `permute(str.substr(1), out + str[0]); ` ` ` ` ` `// Rotate string in a way second character ` ` ` `// moves to the beginning. ` ` ` `rotate(str.begin(), str.begin() + 1, str.end()); ` ` ` `} ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `string str = ` `"ABC"` `; ` ` ` `permute(str, ` `""` `); ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

Output :

ABC ACB BCA BAC CAB CBA

**Method 2 (using next_permute())**

We can use next_permute() that modifies a string so that it stores lexicographically next permutation. If current string is lexicographically largest, i.e., “CBA”, then next_permute() returns false.

We first sort the string, so that it is converted to lexicographically smallest permutation. Then we one by one call next_permutation until it returns false.

`// C++ program to print all permutations with ` `// duplicates allowed using next_permute() ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function to print permutations of string str ` `// using next_permute() ` `void` `permute(string str) ` `{ ` ` ` `// Sort the string in lexicographically ` ` ` `// ascennding order ` ` ` `sort(str.begin(), str.end()); ` ` ` ` ` `// Keep printing next permutation while there ` ` ` `// is next permutation ` ` ` `do` `{ ` ` ` `cout << str << endl; ` ` ` `} ` `while` `(next_permutation(str.begin(), str.end())); ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `string str = ` `"CBA"` `; ` ` ` `permute(str); ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

Output :

ABC ACB BCA BAC CAB CBA

Note that the second method always prints permutations in lexicographically sorted order irrespective of input string.

This article is contributed by **Aditya Goel**. If you like GeeksforGeeks and would like to contribute, you can also write an article and mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above

## Recommended Posts:

- All permutations of a string using iteration
- Distinct permutations of the string | Set 2
- Print all permutations of a string in Java
- Permutations of string such that no two vowels are adjacent
- Print all palindrome permutations of a string
- Time complexity of all permutations of a string
- Count of cyclic permutations having XOR with other binary string as 0
- Check if given string can be formed by two other strings or their permutations
- Write a program to print all permutations of a given string
- Generate all permutations of a string that follow given constraints
- Print all distinct permutations of a given string with duplicates
- Check if a binary string contains all permutations of length k
- Iterative program to generate distinct Permutations of a String
- Number of permutations of a string in which all the occurrences of a given character occurs together
- Print all the palindromic permutations of given string in alphabetic order