# numpy.setdiff1d() function in Python

`numpy.setdiff1d()` function find the set difference of two arrays and return the unique values in arr1 that are not in arr2.

Syntax : numpy.setdiff1d(arr1, arr2, assume_unique = False)

Parameters :
arr1 : [array_like] Input array.
arr2 : [array_like] Input comparison array.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.

Return : [ndarray] 1D array of values in arr1 that are not in arr2. The result is sorted when assume_unique = False, but otherwise only sorted if the input is sorted.

Code #1 :

 `# Python program explaining ` `# numpy.setdiff1d() function ` `   `  `# importing numpy as geek  ` `import` `numpy as geek  ` `  `  `arr1 ``=` `[``5``, ``6``, ``2``, ``3``, ``4``] ` `arr2 ``=` `[``1``, ``2``, ``3``] ` `  `  `gfg ``=` `geek.setdiff1d(arr1, arr2) ` `  `  `print` `(gfg) `

Output :

```[4 5 6]
```

Code #2 :

 `# Python program explaining ` `# numpy.setdiff1d() function ` `   `  `# importing numpy as geek  ` `import` `numpy as geek  ` `  `  `arr1 ``=` `[``1``, ``2``, ``3``, ``4``, ``5``, ``6``, ``7``, ``8``, ``9``] ` `arr2 ``=` `[``1``, ``3``, ``5``, ``7``, ``9``, ``11``, ``13``, ``15``] ` `  `  `gfg ``=` `geek.setdiff1d(arr1, arr2) ` `  `  `print` `(gfg) `

Output :

```[2 4 6 8]
```

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