numpy.setdiff1d() function in Python
Last Updated :
17 May, 2020
numpy.setdiff1d()
function find the set difference of two arrays and return the unique values in arr1 that are not in arr2.
Syntax : numpy.setdiff1d(arr1, arr2, assume_unique = False)
Parameters :
arr1 : [array_like] Input array.
arr2 : [array_like] Input comparison array.
assume_unique : [bool] If True, the input arrays are both assumed to be unique, which can speed up the calculation. Default is False.
Return : [ndarray] 1D array of values in arr1 that are not in arr2. The result is sorted when assume_unique = False, but otherwise only sorted if the input is sorted.
Code #1 :
import numpy as geek
arr1 = [ 5 , 6 , 2 , 3 , 4 ]
arr2 = [ 1 , 2 , 3 ]
gfg = geek.setdiff1d(arr1, arr2)
print (gfg)
|
Output :
[4 5 6]
Code #2 :
import numpy as geek
arr1 = [ 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 ]
arr2 = [ 1 , 3 , 5 , 7 , 9 , 11 , 13 , 15 ]
gfg = geek.setdiff1d(arr1, arr2)
print (gfg)
|
Output :
[2 4 6 8]
Share your thoughts in the comments
Please Login to comment...