numpy.ptp() in Python
Last Updated :
23 Nov, 2021
numpy.ptp()function plays an important role in statistics by finding out Range of given numbers. Range = max value – min value.
Syntax : ndarray.ptp(arr, axis=None, out=None)
Parameters :
arr :input array.
axis :axis along which we want the range value. Otherwise, it will consider arr to be flattened(works on all the axis). axis = 0 means along the column and axis = 1 means working along the row.
out : [ndarray, optional]Different array in which we want to place the result. The array must have same dimensions as expected output.
Return : Range of the array (a scalar value if axis is none) or array with range of values along specified axis.
Code #1: Working
Python
import numpy as np
arr = [ 1 , 2 , 7 , 20 , np.nan]
print ( "arr : " , arr)
print ( "Range of arr : " , np.ptp(arr))
arr = [ 1 , 2 , 7 , 10 , 16 ]
print ( "arr : " , arr)
print ( "Range of arr : " , np.ptp(arr))
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Output :
arr : [1, 2, 7, 20, nan]
Range of arr : nan
arr : [1, 2, 7, 10, 16]
Range of arr : 15
Code #2 :
Python
import numpy as np
arr = [[ 14 , 17 , 12 , 33 , 44 ],
[ 15 , 6 , 27 , 8 , 19 ],
[ 23 , 2 , 54 , 1 , 4 ,]]
print ( "\narr : \n" , arr)
print ( "\nRange of arr, axis = None : " , np.ptp(arr))
print ( "Range of arr, axis = 0 : " , np.ptp(arr, axis = 0 ))
print ( "Min of arr, axis = 1 : " , np.ptp(arr, axis = 1 ))
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Output :
arr :
[[14, 17, 12, 33, 44], [15, 6, 27, 8, 19], [23, 2, 54, 1, 4]]
Range of arr, axis = None : 53
Range of arr, axis = 0 : [ 9 15 42 32 40]
Min of arr, axis = 1 : [32 21 53]
Code #3 :
Python
import numpy as np
arr1 = np.arange( 5 )
print ( "\nInitial arr1 : " , arr1)
np.ptp(arr, axis = 0 , out = arr1)
print ( "Changed arr1(having results) : " , arr1)
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Output :
Initial arr1 : [0 1 2 3 4]
Changed arr1(having results) : [ 9 15 42 32 40]
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