numpy.not_equal() in Python

numpy.not_equal(x1, x2[, out]) : checks whether two element or unequal or not.
Parameters :

x1, x2 : [array_like]Input Array whose elements we want to check
out    : [ndarray, optional]Output array that returns True/False.
A placeholder the same shape as x1 to store the result.

Return :

Boolean array

Code 1 :

 # Python Program illustrating # numpy.not_equal() method     import numpy as geek     a  = geek.not_equal([1., 2.], [1., 3.]) print("Not equal : \n", a, "\n")    b = geek.not_equal([1, 2], [[1, 3],[1, 4]]) print("Not equal : \n", b, "\n")

Output :

Not equal :
[False  True]

Not equal :
[[False  True]
[False  True]]

Code 2 :

 # Python Program illustrating # numpy.not_equal() method      import numpy as geek     # Here we will compare Complex values with int a = geek.array([0 + 1j, 2]) b = geek.array([1,2])    d  = geek.not_equal(a, b) print("Comparing complex with int using .not_equal() : ", d)

Ouput :

Comparing complex with int using .not_equal() :  [ True False]

Code 3 :

 # Python Program illustrating # numpy.not_equal() method      import numpy as geek     # Here we will compare Float with int values a = geek.array([1.1, 1]) b = geek.array([1, 2])     d  = geek.not_equal(a, b) print("\nComparing float with int using .not_equal() : ", d)

Output :

Comparing float with int using .not_equal() :  [ True  True]

Note :
These codes won’t run on online-ID. Please run them on your systems to explore the working
.
This article is contributed by Mohit Gupta_OMG 😀. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

My Personal Notes arrow_drop_up

Article Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.