numpy.ma.is_mask() function | Python
Last Updated :
05 May, 2020
numpy.ma.is_mask()
function return True if parameter m is a valid, standard mask. This function does not check the contents of the input, only that the type is MaskType. In particular, this function returns False if the mask has a flexible dtype.
Syntax : numpy.ma.is_mask(m)
Parameter :
m : [array_like] Array to check.
Return : [bool] True if m.dtype.type is MaskType, False otherwise.
Code #1 :
import numpy as geek
import numpy.ma as ma
m = ma.masked_equal([ 0 , 1 , 2 , 0 , 3 ], 0 )
gfg = ma.is_mask(m)
print (gfg)
|
Output :
False
Code #2 :
import numpy as geek
import numpy.ma as ma
m = [ True , False , True ]
gfg = ma.is_mask(m)
print (gfg)
|
Output :
False
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