numpy.isposinf() in Python
Last Updated :
08 Mar, 2024
The numpy.isposinf() function tests element-wise whether it is positive infinity or not and returns the result as a boolean array.
Syntax :
numpy.isposinf(array, y = None)
Parameters:
array : [array_like]Input array or object whose elements, we need to test for infinity.
y : [array_like]A boolean array with the same shape and type as x to store the result.
Return:
boolean array containing the result. For scalar input, the result is a new boolean with value
True if the input is positive or negative infinity; otherwise the value is False.
For array input, the result is a boolean array with the same shape as the input and the values
are True where the corresponding element of the input is positive or negative infinity;
elsewhere the values are False.
Code 1:
Python
import numpy as geek
print ( "Positive : " , geek.isposinf( 1 ), "\n" )
print ( "Positive : " , geek.isposinf( 0 ), "\n" )
print ( "Positive : " , geek.isposinf(geek.nan), "\n" )
print ( "Positive : " , geek.isposinf(geek.inf), "\n" )
print ( "Positive : " , geek.isposinf(geek.NINF), "\n" )
x = geek.array([ - geek.inf, 0. , geek.inf])
y = geek.array([ 2 , 2 , 2 ])
print ( "Checking for positivity : " , geek.isposinf(x, y))
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Output :
Positive : False
Positive : False
Positive : False
Positive : True
Positive : False
Checking for positivity : [0 0 1]
Code 2 :
Python
import numpy as geek
b = geek.arange( 18 ).reshape( 3 , 6 )
print ( "\n" ,b)
print ( "\nIs Positive Infinity : \n" , geek.isposinf(b))
b = [[geek.inf],
[geek.NINF]]
print ( "\nIs Positive Infinity : \n" , geek.isposinf(b))
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Output :
[[ 0 1 2 3 4 5]
[ 6 7 8 9 10 11]
[12 13 14 15 16 17]]
Is Positive Infinity :
[[False False False False False False]
[False False False False False False]
[False False False False False False]]
Is Positive Infinity :
[[ True]
[False]]
Note :
These codes won’t run on online IDE’s. So please, run them on your systems to explore the working.
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