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numpy.count() in Python

• Last Updated : 10 Oct, 2019

`numpy.core.defchararray.count(arr, substring, start=0, end=None)`: Counts for the non-overlapping occurrence of sub-string in the specified range.

Parameters:
arr : array-like or string to be searched.
substring : substring to search for.
start, end : [int, optional] Range to search in.

Returns : An integer array with the number of non-overlapping occurrences of sub-string.

Code #1:

 `# Python Program illustrating ``# numpy.char.count() method `` ` `import` `numpy as np `` ` `# 2D array ``arr ``=` `[``'vdsdsttetteteAAAa'``, ``'AAAAAAAaattttds'``, ``'AAaaxxxxtt'``, ``'AAaaXDSDdscz'``]`` ` `print` `(``"arr : "``, arr)`` ` `print` `(``"Count of 'tt'"``, np.char.count(arr, ``'tt'``))``print` `(``"Count of 'tt'"``, np.char.count(arr, ``'tt'``, start ``=` `0``))``print` `(``"Count of 'tt'"``, np.char.count(arr, ``'tt'``, start ``=` `8``))`

Output:

```arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']
Count of 'tt' [2 2 1 0]
Count of 'tt' [2 2 1 0]
Count of 'tt' [1 2 1 0]
```

Code #2:

 `# Python Program illustrating ``# numpy.char.count() method ``import` `numpy as np `` ` `# 2D array ``arr ``=` `[``'vdsdsttetteteAAAa'``, ``'AAAAAAAaattttds'``, ``'AAaaxxxxtt'``, ``'AAaaXDSDdscz'``]`` ` `print` `(``"arr : "``, arr)`` ` `print` `(``"Count of 'Aa'"``, np.char.count(arr, ``'Aa'``))``print` `(``"Count of 'Aa'"``, np.char.count(arr, ``'Aa'``, start ``=` `8``))`

Output:

```arr :  ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz']

Count of 'Aa' [1 1 1 1]
Count of 'Aa' [1 0 0 0]
```

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