numpy.ceil() in Python - GeeksforGeeks

numpy.ceil(x[, out]) = ufunc ‘ceil’) : This mathematical function returns the ceil of the elements of array. The ceil of the scalar x is the is the smallest integer i, such that i >= x

Parameters :
a : [array_like] Input array

Return : The ceil of each element with float data-type.

Code #1 : Working

# Python program explaining 
# ceil() function 
import numpy as np 
  
in_array = [.5, 1.5, 2.5, 3.5, 4.5, 10.1] 
print ("Input array : \n", in_array) 
  
ceiloff_values = np.ceil(in_array) 
print ("\nRounded values : \n", ceiloff_values) 
  
  
in_array = [.53, 1.54, .71] 
print ("\nInput array : \n", in_array) 
  
ceiloff_values = np.ceil(in_array) 
print ("\nRounded values : \n", ceiloff_values) 
  
in_array = [.5538, 1.33354, .71445] 
print ("\nInput array : \n", in_array) 
  
ceiloff_values = np.ceil(in_array) 
print ("\nRounded values : \n", ceiloff_values) 

Output :

Input array : 
 [0.5, 1.5, 2.5, 3.5, 4.5, 10.1]

Rounded values : 
 [  1.   2.   3.   4.   5.  11.]

Input array : 
 [0.53, 1.54, 0.71]

Rounded values : 
 [ 1.  2.  1.]

Input array : 
 [0.5538, 1.33354, 0.71445]

Rounded values : 
 [ 1.  2.  1.]

Code #2 : Working

# Python program explaining 
# ceil() function 
import numpy as np 
  
in_array = [1.67, 4.5, 7, 9, 12] 
print ("Input array : \n", in_array) 
  
ceiloff_values = np.ceil(in_array) 
print ("\nRounded values : \n", ceiloff_values) 
  
  
in_array = [133.000, 344.54, 437.56, 44.9, 1.2] 
print ("\nInput array : \n", in_array) 
  
ceiloff_values = np.ceil(in_array) 
print ("\nRounded values upto 2: \n", ceiloff_values) 

Output :

Input array : 
 [1.67, 4.5, 7, 9, 12]

Rounded values : 
 [  2.   5.   7.   9.  12.]

Input array : 
 [133.0, 344.54, 437.56, 44.9, 1.2]

Rounded values upto 2: 
 [ 133.  345.  438.   45.    2.]

References : https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.ceil.html#numpy.ceil
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