A person stands in line of n people, but he doesn’t know exactly which position he occupies. He can say that there are no less than ‘f’ people standing in front of him and no more than ‘b’ people standing behind him. The task is to find the number of different positions he can occupy.
Input: n = 3, f = 1, b = 1 Output: 2 3 is the number of people in the line and there can be no less than 1 people standing
in front of him and no more than 1 people standing behind him.So the positions could be 2 and 3
(if we number the positions starting with 1). Input: n = 5, f = 2, b = 3 Output: 3 In this example the positions are 3, 4, 5.
Approach: Let’s iterate through the each item and check whether it is appropriate to the conditions a<=i-1 and n-i<=b (for i from 1 to n). The first condition can be converted into a+1<=i, and the condition n-i<=b in n-b<=i, then the general condition can be written max(a+1, n-b)<=i and then our answer can be calculated by the formula n-max(a+1, n-b)+1.
Below is the implementation of above approach:
- Number of hours after which the second person moves ahead of the first person if they travel at a given speed
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- Position of a person diametrically opposite on a circle
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- Minimum cost to cover the given positions in a N*M grid
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- Count of Numbers in a Range divisible by m and having digit d in even positions
- Find the sum of the ascii values of characters which are present at prime positions
- Count Numbers in Range with difference between Sum of digits at even and odd positions as Prime
- Count number of triplets with product equal to given number with duplicates allowed
- Find minimum number to be divided to make a number a perfect square
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