Node.js URLSearchParams.getAll()

In URLSearchParams interface, the getAll() method returns all the values of the input search parameter in the form of an array.

Syntax:

URLSearchParams.getAll(name)

Returns: An array of string according to the name-value pairs, else an empty array will be returned.

Parameters:
name – Input the name of the parameter.

Example1:

let url = new URL('https://example.com?par=5&bar=2');
let params = new URLSearchParams(url.search.slice(1));

//Add a second par parameter.
params.append('par', 4);

console.log(params.getAll('par'))'

Output:

['5', '4']

Example2: When input parameter is not present

let url = new URL('https://example.com?par=5&bar=2&bar=7&par=4&bar=9');
let params = new URLSearchParams(url.search.slice(1));

console.log(params.getAll('bar'))'

Output:

['2','7','9']

Supported Browsers:

• Google Chrome
• IE
• Edge
• Opera
• Apple Safari

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