Node.js URLSearchParams.get()

In URLSearchParams interface, the get() method returns the first value of the input search parameter.

Syntax:

URLSearchParams.get(name)

Returns:The string will be returned if the name-value pair is found, else null will be returned.

Parameters:
name – Input the name of the parameter.

Example1: When input parameter is present

var URL = require('url').URL;
let url = new URL('https://example.com/?name=Deepak&age=20');
let params = new URLSearchParams(url.search.substring(1));
let name = params.get("name"); // is the string "Deepak"
let age = parseInt(params.get("age"), 10); // is the number 20
console.log(name)
console.log(age)

Output:

Deepak
20

Example2: When input parameter is not present

var URL = require('url').URL;
let url = new URL('https://example.com/?name=Deepak&age=20');
let params = new URLSearchParams(url.search.substring(1));
let address = params.get("address");
console.log(address)

Output:

null

Supported Browsers:

• Google Chrome
• IE
• Edge
• Opera
• Apple Safari

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