Given N Chocolates and K students, the task is to find how to divide the chocolates such that the difference between the minimum and maximum chocolate received by all students is minimized. Print the value of minimum and maximum chocolate distribution.
Input: N = 7, K = 3 Output: Min = 2, Max = 3 Distribution is 2 2 3 Input: N = 100, K = 10 Output: 10 10 Distribution is 10 10 10 10 10 10 10 10 10 10
Approach: The difference will only be minimized when each student gets an equal number of candies that is N % k = 0 but if N % K != 0 then each student will 1st get (N-N%k)/k amount of candy then the rest N%k amount of candies can be distributed to N%K students by giving them each 1 candy. Thus there will be just 1 more candy than the (N-N%k)/k if N % K != 0 with a student.
Below is the implementation of the above approach:
- Maximum students to pass after giving bonus to everybody and not exceeding 100 marks
- Number of chocolates left after k iterations
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