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Minimize the cost of buying the Objects

  • Last Updated : 15 Apr, 2021

Given ‘T’ which represents the total number of items a person has. ‘P’ represents the price of each item and ‘M’ represents the number of free items he gets free if he buys ‘N’ items. The task is to find the total amount the person has to pay to get T items.
Examples: 
 

Input: T = 13, P = 10, N = 3, M = 1 
Output: Amount = 100 
Explaination: 
Total number of fruit bottle a person has = 13 
Offer available is buy 3 get 1 free 
So, person has to buy 9 Fruit juice bottle to get 3 fruit juice bottle for free. 
Now, since the total number of the bottle is 13 so the person buys 1 bottle at P price.
The total amount the person has to pay = (9 + 1) * 10 i.e 100
Input: T = 12, P = 8, N = 2, M = 1 
Output: Amount = 64 
 

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Approach: 
 

  1. First of all, we should try to get free items as much as possible, so this can reduce the cost.
  2. Divide the total number of items with the sum of N and M because we get M free items when we buy atleast N items.
  3. Then calculate the total number of items for which you have to pay for by subtracting the free items from the total number of items
  4. Finally the price can be calculated by multiplying the cost of one item with the total number of items.

Below is the implementation of the above approach: 
 

C++




// C++ program of above approach
#include <bits/stdc++.h>
using namespace std;
 
// Function that will calculate the price
int totalPay(int totalItems, int priceOfOneItem,
             int N, int M)
{
    int freeItems = 0, actual = 0;
 
    // Calculate the number of items
    // we can get for free
    freeItems = totalItems / (N + M);
 
    // Calculate the number of items
    // we will have to pay the price for
    actual = totalItems - freeItems;
 
    // Calculate the price
    int amount = actual * priceOfOneItem;
 
    return amount;
}
 
// Driver code
int main()
{
    int T = 12, P = 8;
    int N = 2, M = 1;
 
    // Calling function
    cout << "Amount = "
         << totalPay(T, P, N, M);
 
    return 0;
}

Java




// Java implementation of the approach
class GFG
{
 
// Function that will calculate the price
static int totalPay(int totalItems,
                    int priceOfOneItem,
                    int N, int M)
{
    int freeItems = 0, actual = 0;
 
    // Calculate the number of items
    // we can get for free
    freeItems = totalItems / (N + M);
 
    // Calculate the number of items
    // we will have to pay the price for
    actual = totalItems - freeItems;
 
    // Calculate the price
    int amount = actual * priceOfOneItem;
 
    return amount;
}
 
// Driver code
public static void main(String[] args)
{
    int T = 12, P = 8;
    int N = 2, M = 1;
 
    // Calling function
    System.out.print("Amount = " +
                      totalPay(T, P, N, M));
}
}
 
// This code is contributed by 29AjayKumar

Python3




# Python3 program of above approach
 
# Function that will calculate the price
def totalPay(totalItems, priceOfOneItem, N, M):
    freeItems = 0
    actual = 0
 
    # Calculate the number of items
    # we can get for free
    freeItems = totalItems // (N + M)
 
    # Calculate the number of items
    # we will have to pay the price for
    actual = totalItems - freeItems
 
    # Calculate the price
    amount = actual * priceOfOneItem
 
    return amount
 
# Driver code
T = 12
P = 8
N = 2
M = 1
 
# Calling function
print("Amount = ", totalPay(T, P, N, M))
 
# This code is contributed by Mohit Kumar

C#




// C# implementation of the approach
using System;
class GFG
{
 
// Function that will calculate the price
static int totalPay(int totalItems,
                    int priceOfOneItem,
                    int N, int M)
{
    int freeItems = 0, actual = 0;
 
    // Calculate the number of items
    // we can get for free
    freeItems = totalItems / (N + M);
 
    // Calculate the number of items
    // we will have to pay the price for
    actual = totalItems - freeItems;
 
    // Calculate the price
    int amount = actual * priceOfOneItem;
 
    return amount;
}
 
// Driver code
public static void Main(String[] args)
{
    int T = 12, P = 8;
    int N = 2, M = 1;
 
    // Calling function
    Console.Write("Amount = " +
                   totalPay(T, P, N, M));
}
}
 
// This code is contributed by PrinciRaj1992

Javascript




<script>
 
// Javascript program of above approach
 
// Function that will calculate the price
function totalPay(totalItems, priceOfOneItem,
             N, M)
{
    var freeItems = 0, actual = 0;
 
    // Calculate the number of items
    // we can get for free
    freeItems = totalItems / (N + M);
 
    // Calculate the number of items
    // we will have to pay the price for
    actual = totalItems - freeItems;
 
    // Calculate the price
    var amount = actual * priceOfOneItem;
 
    return amount;
}
 
// Driver code
var T = 12, P = 8;
var N = 2, M = 1;
// Calling function
document.write( "Amount = "
     + totalPay(T, P, N, M));
 
</script>
Output: 
Amount = 64

 




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