# Minimize the cost of buying the Objects

Given **‘T’** which represents the total number of items a person has. **‘P’** represents the price of each item and **‘M’** represents the number of free items he gets **free** if he buys **‘N’** items. The task is to find the total amount the person has to pay to get T items.

**Examples:**

Input:T = 13, P = 10, N = 3, M = 1

Output:Amount = 100

Explaination:

Total number of fruit bottle a person has = 13

Offer available is buy 3 get 1 free

So, person has to buy 9 Fruit juice bottle to get 3 fruit juice bottle for free.

Now, since the total number of the bottle is 13 so the person buys 1 bottle at P price.The total amount the person has to pay = (9 + 1) * 10 i.e 100

Input:T = 12, P = 8, N = 2, M = 1

Output:Amount = 64

**Approach:**

- First of all, we should try to get free items as much as possible, so this can reduce the cost.
- Divide the total number of items with the sum of
**N**and**M**because we get**M**free items when we buy atleast**N**items. - Then calculate the total number of items for which you have to pay for by subtracting the free items from the total number of items
- Finally the price can be calculated by multiplying the cost of one item with the total number of items.

Below is the implementation of the above approach:

## C++

`// C++ program of above approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `// Function that will calculate the price ` `int` `totalPay(` `int` `totalItems, ` `int` `priceOfOneItem, ` ` ` `int` `N, ` `int` `M) ` `{ ` ` ` `int` `freeItems = 0, actual = 0; ` ` ` ` ` `// Calculate the number of items ` ` ` `// we can get for free ` ` ` `freeItems = totalItems / (N + M); ` ` ` ` ` `// Calculate the number of items ` ` ` `// we will have to pay the price for ` ` ` `actual = totalItems - freeItems; ` ` ` ` ` `// Calculate the price ` ` ` `int` `amount = actual * priceOfOneItem; ` ` ` ` ` `return` `amount; ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `int` `T = 12, P = 8; ` ` ` `int` `N = 2, M = 1; ` ` ` ` ` `// Calling function ` ` ` `cout << ` `"Amount = "` ` ` `<< totalPay(T, P, N, M); ` ` ` ` ` `return` `0; ` `} ` |

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## Java

`// Java implementation of the approach ` `class` `GFG ` `{ ` ` ` `// Function that will calculate the price ` `static` `int` `totalPay(` `int` `totalItems, ` ` ` `int` `priceOfOneItem, ` ` ` `int` `N, ` `int` `M) ` `{ ` ` ` `int` `freeItems = ` `0` `, actual = ` `0` `; ` ` ` ` ` `// Calculate the number of items ` ` ` `// we can get for free ` ` ` `freeItems = totalItems / (N + M); ` ` ` ` ` `// Calculate the number of items ` ` ` `// we will have to pay the price for ` ` ` `actual = totalItems - freeItems; ` ` ` ` ` `// Calculate the price ` ` ` `int` `amount = actual * priceOfOneItem; ` ` ` ` ` `return` `amount; ` `} ` ` ` `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` ` ` `int` `T = ` `12` `, P = ` `8` `; ` ` ` `int` `N = ` `2` `, M = ` `1` `; ` ` ` ` ` `// Calling function ` ` ` `System.out.print(` `"Amount = "` `+ ` ` ` `totalPay(T, P, N, M)); ` `} ` `} ` ` ` `// This code is contributed by 29AjayKumar ` |

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## Python3

`# Python3 program of above approach ` ` ` `# Function that will calculate the price ` `def` `totalPay(totalItems, priceOfOneItem, N, M): ` ` ` `freeItems ` `=` `0` ` ` `actual ` `=` `0` ` ` ` ` `# Calculate the number of items ` ` ` `# we can get for free ` ` ` `freeItems ` `=` `totalItems ` `/` `/` `(N ` `+` `M) ` ` ` ` ` `# Calculate the number of items ` ` ` `# we will have to pay the price for ` ` ` `actual ` `=` `totalItems ` `-` `freeItems ` ` ` ` ` `# Calculate the price ` ` ` `amount ` `=` `actual ` `*` `priceOfOneItem ` ` ` ` ` `return` `amount ` ` ` `# Driver code ` `T ` `=` `12` `P ` `=` `8` `N ` `=` `2` `M ` `=` `1` ` ` `# Calling function ` `print` `(` `"Amount = "` `, totalPay(T, P, N, M)) ` ` ` `# This code is contributed by Mohit Kumar ` |

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## C#

// C# implementation of the approach

using System;

class GFG

{

// Function that will calculate the price

static int totalPay(int totalItems,

int priceOfOneItem,

int N, int M)

{

int freeItems = 0, actual = 0;

// Calculate the number of items

// we can get for free

freeItems = totalItems / (N + M);

// Calculate the number of items

// we will have to pay the price for

actual = totalItems – freeItems;

// Calculate the price

int amount = actual * priceOfOneItem;

return amount;

}

// Driver code

public static void Main(String[] args)

{

int T = 12, P = 8;

int N = 2, M = 1;

// Calling function

Console.Write(“Amount = ” +

totalPay(T, P, N, M));

}

}

// This code is contributed by PrinciRaj1992

**Output:**

Amount = 64

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