math.Ldexp() Function in Golang with Examples
Last Updated :
28 Apr, 2020
Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. This package provides Ldexp() function which is used to find the inverse of Frexp. Or in other words, this function return frac × 2**exp. So, you need to add a math package in your program with the help of the import keyword to access the Ldexp() function.
Syntax:
func Ldexp(frac float64, exp int) float64
- If Ldexp(±0, exp), then this function will return ±0.
- If Ldexp(±Inf, exp), then this function will return ±Inf.
- If Ldexp(NaN, exp), then this function will return NaN.
Example 1:
package main
import (
"fmt"
"math"
)
func main() {
res_1 := math.Ldexp(1.1, 5)
res_2 := math.Ldexp(math.Inf(-1), 2)
res_3 := math.Ldexp(+0, 1)
res_4 := math.Ldexp(2, 5)
res_5 := math.Ldexp(math.NaN(), 1)
fmt.Printf( "\nResult 1: %f" , res_1)
fmt.Printf( "\nResult 2: %f" , res_2)
fmt.Printf( "\nResult 3: %f" , res_3)
fmt.Printf( "\nResult 4: %f" , res_4)
fmt.Printf( "\nResult 5: %f" , res_5)
}
|
Output:
Result 1: 35.200000
Result 2: -Inf
Result 3: 0.000000
Result 4: 64.000000
Result 5: NaN
Example 2:
package main
import (
"fmt"
"math"
)
func main() {
nvalue_1 := math.Ldexp(2, 5)
nvalue_2 := math.Ldexp(6, 2)
res := nvalue_1 + nvalue_2
fmt.Println( "Result 1: " , nvalue_1)
fmt.Println( "Result 2: " , nvalue_2)
fmt.Println( "Sum of Result 1 and Result 2: " , res)
}
|
Output:
Result 1: 64
Result 2: 24
Sum of Result 1 and Result 2: 88
Share your thoughts in the comments
Please Login to comment...