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math.Expm1 Function() in Golang With Examples

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  • Last Updated : 01 Apr, 2020
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Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find base-e exponential of the specified number minus 1, i.e., e**a -1 with the help of Expm1() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access Expm1() function.

Syntax:

func Expm1(a float64) float64
  • If you pass +Inf in this function, then this function will return +Inf.
  • If you pass -Inf in this function, then this function will return -1.
  • In this function, very large values overflow to -1 or +Inf.
  • If you pass NaN in this function, then this function will return NaN.

Example 1:




// Golang program to illustrate the Exmp1 function
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Using Expm1() function
    res_1 := math.Expm1(4)
    res_2 := math.Expm1(-1)
    res_3 := math.Expm1(math.Inf(1))
    res_4 := math.Expm1(math.NaN())
  
    // Displaying the result
    fmt.Printf("Result 1: %.1f", res_1)
    fmt.Printf("\nResult 2: %.1f", res_2)
    fmt.Printf("\nResult 3: %.1f", res_3)
    fmt.Printf("\nResult 4: %.1f", res_4)
  
}

Output:

Result 1: 53.6
Result 2: -0.6
Result 3: +Inf
Result 4: NaN

Example 2:




// Golang program to illustrate the Exmp1 function
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Using Expm1() function
    nvalue_1 := math.Expm1(7.3)
    nvalue_2 := math.Expm1(-3)
    res := nvalue_1 + nvalue_2
    fmt.Printf("%.1f + %.1f = %.1f",
            nvalue_1, nvalue_2, res)
  
}

Output:

1479.3 + -1.0 = 1478.3 

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