math.Ilogb() Function in Golang With Examples
Last Updated :
13 Apr, 2020
Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You can find the binary exponent of the specified number as an integer with the help of ILogb() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the ILogb() function.
Syntax:
func Ilogb(a float64) int
- If Ilogb(±Inf), then this function will return MaxInt32.
- If Ilogb(0), then this function will return MinInt32.
- If Ilogb(NaN), then this function will return MaxInt32.
Example 1:
package main
import (
"fmt"
"math"
)
func main() {
res_1 := math.Ilogb(math.Inf(-1))
res_2 := math.Ilogb(math.Inf(1))
res_3 := math.Ilogb(0)
res_4 := math.Ilogb(1)
res_5 := math.Ilogb(math.NaN())
fmt.Printf( "\nResult 1: %d" , res_1)
fmt.Printf( "\nResult 2: %d" , res_2)
fmt.Printf( "\nResult 3: %d" , res_3)
fmt.Printf( "\nResult 4: %d" , res_4)
fmt.Printf( "\nResult 5: %d" , res_5)
}
|
Output:
Result 1: 2147483647
Result 2: 2147483647
Result 3: -2147483648
Result 4: 0
Result 5: 2147483647
Example 2:
package main
import (
"fmt"
"math"
)
func main() {
nvalue_1 := math.Ilogb(math.Inf(-1))
nvalue_2 := math.Ilogb(math.Inf(1))
res := nvalue_1 + nvalue_2
fmt.Printf( "%d + %d = %d" ,
nvalue_1, nvalue_2, res)
}
|
Output:
2147483647 + 2147483647 = -2
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