LongStream mapToObj() in Java
Last Updated :
06 Dec, 2018
LongStream mapToObj() returns an object-valued Stream consisting of the results of applying the given function.
Note : LongStream mapToObj() is a intermediate operation. These operations are always lazy. Intermediate operations are invoked on a Stream instance and after they finish their processing, they give a Stream instance as output.
Syntax :
<U> Stream<U> mapToObj(LongFunction<? extends U> mapper)
Parameters :
- U : The element type of the new stream.
- Stream : A sequence of elements supporting sequential and parallel aggregate operations.
- LongFunction : Represents a function that accepts a long-valued argument and produces a result.
- mapper : A stateless function to apply to each element.
Return Value : The function returns an object-valued Stream consisting of the results of applying the given function.
Example 1 :
import java.util.*;
import java.util.stream.Stream;
import java.util.stream.LongStream;
class GFG {
public static void main(String[] args)
{
LongStream stream = LongStream.range(3L, 8L);
Stream<String> stream1 = stream.mapToObj(num
-> Long.toBinaryString(num));
stream1.forEach(System.out::println);
}
}
|
Output :
11
100
101
110
111
Example 2 :
import java.util.*;
import java.math.BigInteger;
import java.util.stream.Stream;
import java.util.stream.LongStream;
class GFG {
public static void main(String[] args)
{
LongStream stream = LongStream.of(3L, 5L, 7L, 9L, 11L);
Stream<BigInteger> stream1 = stream
.mapToObj(BigInteger::valueOf);
stream1.forEach(num -> System.out.println(num.add(BigInteger.TEN)));
}
}
|
Output :
13
15
17
19
21
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