LongStream mapToInt() in Java with Examples
Last Updated :
06 Dec, 2018
LongStream mapToInt() returns an IntStream consisting of the results of applying the given function to the elements of this stream.
Note : LongStream mapToInt() is a intermediate operation. These operations are always lazy. Intermediate operations are invoked on a Stream instance and after they finish their processing, they give a Stream instance as output.
Syntax :
LongStream mapToInt(LongToIntFunction mapper)
Parameters :
- LongStream : A sequence of primitive long-valued elements. This is the long primitive specialization of Stream.
- mapper : A stateless function to apply to each element.
Return Value : The function returns an IntStream consisting of the results of applying the given function to the elements of this stream.
Example 1 :
import java.util.*;
import java.util.stream.IntStream;
import java.util.stream.LongStream;
class GFG {
public static void main(String[] args)
{
LongStream stream = LongStream.of(2L, 4L, 6L, 8L, 10L);
IntStream stream1 = stream.mapToInt(num -> ( int ) num);
stream1.forEach(System.out::println);
}
}
|
Output :
2
4
6
8
10
Example 2 :
import java.util.*;
import java.util.stream.IntStream;
import java.util.stream.LongStream;
class GFG {
public static void main(String[] args)
{
LongStream stream = LongStream.of(1L, 2L, 3L, 4L, 5L);
IntStream stream1 = stream.mapToInt(num ->
( int ) num + Integer.MAX_VALUE);
stream1.forEach(System.out::println);
}
}
|
Output :
-2147483648
-2147483647
-2147483646
-2147483645
-2147483644
Example 3 :
import java.util.*;
import java.util.stream.IntStream;
import java.util.stream.LongStream;
class GFG {
public static void main(String[] args)
{
LongStream stream = LongStream.range(2L, 7L);
IntStream stream1 = stream.mapToInt(num ->
( int ) num - 2 );
stream1.forEach(System.out::println);
}
}
|
Output :
0
1
2
3
4
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