Java Program To Check Whether The Length Of Given Linked List Is Even Or Odd
Last Updated :
24 Jan, 2023
Given a linked list, the task is to make a function which checks whether the length of the linked list is even or odd. Examples:
Input : 1->2->3->4->NULL
Output : Even
Input : 1->2->3->4->5->NULL
Output : Odd
Method 1: Count the codes linearly
Traverse the entire Linked List and keep counting the number of nodes. As soon as the loop is finished, we can check if the count is even or odd. You may try it yourself.
Method 2: Stepping 2 nodes at a time
Approach:
1. Take a pointer and move that pointer two nodes at a time
2. At the end, if the pointer is NULL then length is Even, else Odd.
Java
import java.io.*;
class GfG{
static class Node
{
int data;
Node next;
}
static int LinkedListLength(Node head)
{
while (head != null &&
head.next != null )
{
head = head.next.next;
}
if (head == null )
return 0 ;
return 1 ;
}
static void push(Node head, i
nt info)
{
Node node = new Node();
node.data = info;
node.next = (head);
(head) = node;
}
public static void main(String[] args)
{
Node head = null ;
push(head, 4 );
push(head, 5 );
push(head, 7 );
push(head, 2 );
push(head, 9 );
push(head, 6 );
push(head, 1 );
push(head, 2 );
push(head, 0 );
push(head, 5 );
push(head, 5 );
int check =
LinkedListLength(head);
if (check == 0 )
{
System.out.println( "Odd" );
}
else
{
System.out.println( "Even" );
}
}
}
|
Output:
Odd
Time Complexity: O(n)
Auxiliary Space: O(1)
Using Recursion
Java
import java.io.*;
class GfG{
static class Node
{
int data;
Node next;
}
static int LinkedListLength(Node head)
{
if (head == null ) return 0 ;
return 1 +LinkedListLength(head.next);
}
static void push(Node head, int info)
{
Node node = new Node();
node.data = info;
node.next = (head);
(head) = node;
}
public static void main(String[] args)
{
Node head = null ;
push(head, 4 );
push(head, 5 );
push(head, 7 );
push(head, 2 );
push(head, 9 );
push(head, 6 );
push(head, 1 );
push(head, 2 );
push(head, 0 );
push(head, 5 );
push(head, 5 );
int check =
LinkedListLength(head);
if (check == 0 )
{
System.out.println( "Odd" );
}
else
{
System.out.println( "Even" );
}
}
}
|
Time Complexity: O(n)
Auxiliary Space: O(n)
Please refer complete article on Check whether the length of given linked list is Even or Odd for more details!
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