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Java | Exception Handling | Question 4

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class Base extends Exception {}
class Derived extends Base  {}
public class Main {
  public static void main(String args[]) {
   // some other stuff
   try {
       // Some monitored code
       throw new Derived();
    catch(Base b)     { 
       System.out.println("Caught base class exception"); 
    catch(Derived d)  { 
       System.out.println("Caught derived class exception"); 

(A) Caught base class exception
(B) Caught derived class exception
(C) Compiler Error because derived is not throwable
(D) Compiler Error because base class exception is caught before derived class

Answer: (D)

Explanation: See Catching base and derived classes as exceptions

Following is the error in below program error: exception Derived has already been caught
    catch(Derived d)  { System.out.println("Caught derived class exception"); } 

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Last Updated : 28 Jun, 2021
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