issuperset() in Python

Python set issuperset() method returns True if all elements of a set A occupies set B which is passed as an argument and returns false if all elements of B are not present in A. This means if A is a superset of B then it returns true; else False

Python issuperset() Syntax:

A.issuperset(B)
checks whether A is a superset of B or not.

Python issuperset() Returns:

True if A is a superset of B; otherwise false.

Python issuperset() example

Example 1: Working of issubset() with two sets

Python

# Python program to demonstrate working of
# issuperset().

A = {4, 1, 3, 5}
B = {6, 0, 4, 1, 5, 0, 3, 5}

print("A.issuperset(B) : ", A.issuperset(B))

# B is superset of A
print("B.issuperset(A) : ", B.issuperset(A))

Output:

A.issuperset(B) :  False
B.issuperset(A) :  True

Example 2: Working of issubset() with three sets

Python

# Python program to demonstrate working
# of issuperset().

A = {1, 2, 3}
B = {1, 2, 3, 4, 5}
C = {1, 2, 4, 5}

print("A.issuperset(B) : ", A.issuperset(B))
print("B.issuperset(A) : ", B.issuperset(A))
print("A.issuperset(C) : ", A.issuperset(C))
print("C.issuperset(B) : ", C.issuperset(B))

Output:

A.issuperset(B) :  False
B.issuperset(A) :  True
A.issuperset(C) :  False
C.issuperset(B) :  False