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Finding the Inverse Hyperbolic Tangent of Specified Number in Golang
  • Last Updated : 01 Apr, 2020

Go language provides inbuilt support for basic constants and mathematical functions to perform operations on the numbers with the help of the math package. You are allowed to find the inverse hyperbolic tangent of the specified number with the help of the Atanh() function provided by the math package. So, you need to add a math package in your program with the help of the import keyword to access the Atanh() function.

Syntax:

func Atanh(y float64) float64
  • If you pass 1 in this function, then this function will return +Inf.
  • If you pass -1 in this function, then this function will return -Inf.
  • If you pass -0 or +0 in this function, then this function will return -0 or +0.
  • If you pass NaN in this function, then this function will return NaN.
  • If y < -1 or y > 1, then this function will return NaN.

Example 1:




// Golang program to illustrate how to find the
// inverse hyperbolic tangent of the given number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding the inverse hyperbolic
    // tangent of the given value
    // Using Atanh() function
    res_1 := math.Atanh(math.Pi / 4)
    res_2 := math.Atanh(math.Inf(-3))
    res_3 := math.Atanh(0)
    res_4 := math.Atanh(math.NaN())
    res_5 := math.Atanh(-1)
  
    // Displaying the result
    fmt.Printf("Result 1: %.1f", res_1)
    fmt.Printf("\nResult 2: %.1f", res_2)
    fmt.Printf("\nResult 3: %.1f", res_3)
    fmt.Printf("\nResult 4: %.1f", res_4)
    fmt.Printf("\nResult 5: %.1f", res_5)
}

Output:

Result 1: 1.1
Result 2: NaN
Result 3: 0.0
Result 4: NaN
Result 5: -Inf

Example 2:




// Golang program to illustrate how to find the
// inverse hyperbolic tangent of the given number
  
package main
  
import (
    "fmt"
    "math"
)
  
// Main function
func main() {
  
    // Finding inverse hyperbolic 
    // tangent of the given number
    nvalue_1 := math.Atanh(math.Pi / 3)
    nvalue_2 := math.Atanh(math.Pi / 6)
  
    // Sum of the given values
    res := nvalue_1 + nvalue_2
  
    // Displaying results
    fmt.Printf("%.1f + %.1f = %.1f"
            nvalue_1, nvalue_2, res)
  
}

Output:

NaN + 0.6 = NaN



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