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Finding the Inverse Tangent of Complex Number in Golang

Last Updated : 27 Mar, 2020
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Go language provides inbuilt support for basic constants and mathematical functions for complex numbers with the help of the cmplx package. You are allowed to find the inverse tangent of the specified complex number with the help of the Atan() function provided by the math/cmplx package. So, you need to add a math/cmplx package in your program with the help of the import keyword to access the Atan() function.

Syntax:

func Atan(x complex128) complex128

Let us discuss this concept with the help of the given examples:

Example 1:




// Golang program to illustrate how to find
// Inverse Tangent of Complex Number
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    // Finding inverse tangent of the 
    // specified complex number
    // Using Atan() function
    res_1 := cmplx.Atan(3 + 5i)
    res_2 := cmplx.Atan(-4 + 8i)
    res_3 := cmplx.Atan(-8 - 7i)
  
    // Displaying the result
    fmt.Println("Result 1:", res_1)
    fmt.Println("Result 2:", res_2)
    fmt.Println("Result 3:", res_3)
}


Output:

Result 1: (1.4808695768986575+0.14694666622552977i)
Result 2: (-1.5203354344612496+0.10008092715193644i)
Result 3: (-1.4998477994928145-0.06171501948288145i)

Example 2:




// Golang program to illustrate how to find
// Inverse Tangent of Complex Number
  
package main
  
import (
    "fmt"
    "math/cmplx"
)
  
// Main function
func main() {
  
    cnumber_1 := complex(5, 7)
    cnumber_2 := complex(6, 9)
  
    // Finding inverse tangent
    cvalue_1 := cmplx.Atan(cnumber_1)
    cvalue_2 := cmplx.Atan(cnumber_2)
  
    // Sum of two inverse tangent values
    res := cvalue_1 + cvalue_2
  
    // Displaying results
    fmt.Println("Complex Number 1: ", cnumber_1)
    fmt.Println("Inverse tangent 1: ", cvalue_1)
  
    fmt.Println("Complex Number 2: ", cnumber_2)
    fmt.Println("Inverse tangent 2: ", cvalue_2)
    fmt.Println("Final sum: ", res)
  
}


Output:

Complex Number 1:  (5+7i)
Inverse tangent 1:  (1.502726846368326+0.09444062638970716i)
Complex Number 2:  (6+9i)
Inverse tangent 2:  (1.5192555225335465+0.07687117493699018i)
Final sum:  (3.0219823689018726+0.17131180132669732i)


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