# Finding the Inverse Tangent of Complex Number in Golang

Last Updated : 27 Mar, 2020

Go language provides inbuilt support for basic constants and mathematical functions for complex numbers with the help of the cmplx package. You are allowed to find the inverse tangent of the specified complex number with the help of the Atan() function provided by the math/cmplx package. So, you need to add a math/cmplx package in your program with the help of the import keyword to access the Atan() function.

Syntax:

`func Atan(x complex128) complex128`

Let us discuss this concept with the help of the given examples:

Example 1:

 `// Golang program to illustrate how to find ` `// Inverse Tangent of Complex Number ` `package main ` ` `  `import ( ` `    ``"fmt"` `    ``"math/cmplx"` `) ` ` `  `// Main function ` `func main() { ` ` `  `    ``// Finding inverse tangent of the  ` `    ``// specified complex number ` `    ``// Using Atan() function ` `    ``res_1 := cmplx.Atan(3 + 5i) ` `    ``res_2 := cmplx.Atan(-4 + 8i) ` `    ``res_3 := cmplx.Atan(-8 - 7i) ` ` `  `    ``// Displaying the result ` `    ``fmt.Println(``"Result 1:"``, res_1) ` `    ``fmt.Println(``"Result 2:"``, res_2) ` `    ``fmt.Println(``"Result 3:"``, res_3) ` `} `

Output:

```Result 1: (1.4808695768986575+0.14694666622552977i)
Result 2: (-1.5203354344612496+0.10008092715193644i)
Result 3: (-1.4998477994928145-0.06171501948288145i)
```

Example 2:

 `// Golang program to illustrate how to find ` `// Inverse Tangent of Complex Number ` ` `  `package main ` ` `  `import ( ` `    ``"fmt"` `    ``"math/cmplx"` `) ` ` `  `// Main function ` `func main() { ` ` `  `    ``cnumber_1 := complex(5, 7) ` `    ``cnumber_2 := complex(6, 9) ` ` `  `    ``// Finding inverse tangent ` `    ``cvalue_1 := cmplx.Atan(cnumber_1) ` `    ``cvalue_2 := cmplx.Atan(cnumber_2) ` ` `  `    ``// Sum of two inverse tangent values ` `    ``res := cvalue_1 + cvalue_2 ` ` `  `    ``// Displaying results ` `    ``fmt.Println(``"Complex Number 1: "``, cnumber_1) ` `    ``fmt.Println(``"Inverse tangent 1: "``, cvalue_1) ` ` `  `    ``fmt.Println(``"Complex Number 2: "``, cnumber_2) ` `    ``fmt.Println(``"Inverse tangent 2: "``, cvalue_2) ` `    ``fmt.Println(``"Final sum: "``, res) ` ` `  `} `

Output:

```Complex Number 1:  (5+7i)
Inverse tangent 1:  (1.502726846368326+0.09444062638970716i)
Complex Number 2:  (6+9i)
Inverse tangent 2:  (1.5192555225335465+0.07687117493699018i)
Final sum:  (3.0219823689018726+0.17131180132669732i)
```

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